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2 years ago

PLEASE HELP ME IM STUCK ON MY MATH EXAMS

Mathematics

1 answer:

ra1l [238]2 years ago

4 0

Answer:

yes I agree on the terms and policy here and my language I'm not sure what to think we are good to be in touch with my mom to call me when I get your address so we are working with my family in each group of peoples

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Suppose Team A has a 0.75 probability to win their next game and Team B has a 0.85 probability to win their next game. Assume th

vovangra [49]

Answer:

B has a higer probability

Step-by-step explanation:

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3 years ago

How to find the volume of a cone? Height- 8 in. Diameter- 7 in.

mestny [16]

The formula for the volume of a cone is V = $\pi r^{2} \frac{h}{3}$

So the answer is 102.63

4 0

3 years ago

Compare the functions below:

rjkz [21]

$f(x)\to y_{max}=4\\\\g(x)=4\cos(2x-\pi)-2\to y_{max}=2\\\\h(x)=-(x-5)^2+3\to y_{max}=3$

Answer: a. f(x)

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3 years ago

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A specimen of charcoal found at Stonehenge contains 63% as much Carbon-14 as a sample of present-day charcoal. What is the age o

seraphim [82]

Since we are given with the identity of the chemical as Carbon-14, we obtain the half-life of the chemical from a reliable source and get a value of 5730 years. The equation that we are going to use for this item is,
A(t)/A(0) = (0.50)^(n/5730)
where A(t) is the current amount, A(0) is the initial amount and n is the number of years. We know from the given that the ratio of A(t) and A(0) is equal to 0.63. Substituting this to the given,
0.63 = 0.50^(n/5730)
n = 3819.48
Thus, the sample is approximately 3819.5 years old.

5 0

3 years ago

A professor believes the students in a statistics class this term are more creative than most other students attending the unive

djverab [1.8K]

Answer:

Correct option: B

Step-by-step explanation:

The professor can perform a One-mean t-test to determine whether the average score of the students in his class is more than the average score of all the students attending university.

A t-test will be used instead of the z-test because the population standard deviation is not provided instead it is estimated by the sample standard deviation.

The hypothesis for this test can be defined as follows:

H₀: The average score of the students in his class is not more then the entire university, i.e. μ ≤ 35.

Hₐ: The average score of the students in his class is more then the entire university, i.e. μ > 35.

Given:

$\bar x=40\\SE_{\bar x}=1.63$

The test statistic is:

$t=\frac{\bar x-\mu}{SE_{\bar x}}=\frac{40-35}{1.63}=3.0674\approx3.07$

Thus, the correct option is (B).

4 0

3 years ago