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pishuonlain [190]
3 years ago
11

PLEASE HELP ME IM STUCK ON MY MATH EXAMS

Mathematics
1 answer:
ra1l [238]3 years ago
4 0

Answer:

yes I agree on the terms and policy here and my language I'm not sure what to think we are good to be in touch with my mom to call me when I get your address so we are working with my family in each group of peoples

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What is the area of the hexagon
ValentinkaMS [17]
1 Answer. Suryin =) . 96√3 cm. Explanation: Area of regular hexagon : A=3√32a2. a is the side which is 8 cm. A=3√32(82). A=3√32(64). A= 192√32.
7 0
3 years ago
For 11-13, solve each equation for the given value of x
S_A_V [24]

Answer:

11--12---13 you find the number that is always in the middle of both numbers

8 0
3 years ago
Jim had some dimes, quarters, and nickels. First, he counted only the dimes and quarters and found that he had 9 coins. Then, he
devlian [24]

Answer:

he has 5 quarters, 4 dimes and 6 nickles

Step-by-step explanation:

you can find this by adding the amount of coins he counted in total (19 coins) and the total amount of coins he had (15), the subtract 15 from 19 which will give you 4, this means that in both times he counted coins, only 4 of those coins in both counts were the same, and if you see, they mention dimes twice in both counts, this means the 4 coins that are shared between both counts are dimes, then dubstract 4 from 9, that's 5 so it's the 5 quarters, and substract 4 from 10 which will give you the 6 nickles

4 0
3 years ago
What is 5/60 simplified i need helps
Pavel [41]
Divide the numerator and denominator by 5 and get 1/12
so 5/60 simplified is 1/12

Hope this helps! :D
4 0
3 years ago
Read 2 more answers
A USA Today/Gallup poll asked a group of unemployed and underemployed Americans if they have had major problems in their relatio
Tems11 [23]

Answer:

Null hypothesis: <em>H₀</em>: <em>p</em>₁ = <em>p</em>₂.

Alternate hypothesis: <em>H₀</em>: <em>p</em>₁ ≠ <em>p</em>₂.

Step-by-step explanation:

A statistical experiment is conducted to determine whether the proportions of unemployed and underemployed people who had relationship problems were different.

Let <em>p</em>₁ = the proportion of unemployed people who had relationship problems and <em>p</em>₂ = the proportion of underemployed people who had relationship problems.

A hypothesis test for difference between proportions, can be conducted to determine if there is any difference between the two population proportions.

Use a <em>z</em>-test for the test statistic.

The hypothesis test is:

<em>H₀</em>: There is no difference between the proportions of unemployed and underemployed people who had relationship problems, i.e. <em>p</em>₁ = <em>p</em>₂.

<em>Hₐ</em>: There is a significant difference between the proportions of unemployed and underemployed people who had relationship problems, i.e. <em>p</em>₁ ≠ <em>p</em>₂.

5 0
3 years ago
Read 2 more answers
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