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Shalnov [3]
3 years ago
11

Please help me answer this question

Mathematics
1 answer:
SOVA2 [1]3 years ago
8 0
Well knowing that it’s 5 1/4 and the cost of paint is 13.99, I’m going to assume to multiply by the given product which is 13.99 by one quarter (which is 25)
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I cant seem to get one of these answers when i work it out. please help​
lisov135 [29]

Answer:

first option

Step-by-step explanation:

To obtain ( f ○ g)(x) substitute x = g(x) into f(x) , that is

f(\frac{1}{2x} )

= \frac{2}{\frac{1}{2x}+3 } ( multiply numerator/ denominator by 2x to clear the fraction

= \frac{2(2x)}{2x(\frac{1}{2x}+3) }

= \frac{4x}{1+6x}

3 0
3 years ago
10 points for this question!!!!!! Please answer like
alexdok [17]
Box one ratios
Box two 35:2= 70:4

7 0
3 years ago
A simple random sample was taken of 44 water bottles from a bottling plant’s warehouse. The dissolved oxygen content (in mg/L) w
Margarita [4]

Answer:

(a) Test statistic is -2.85 and p-value is 0.0022

(b) Reject the null hypothesis. The population mean of dissolved oxygen content is not equal to 10 mg/L

Step-by-step explanation:

H0: mu equals 10

Ha: mu not equals 10

The test is a two-tailed test because the alternate hypothesis is expressed using not equal to

(a) Test statistic (z) = (sample mean - population mean) ÷ (sd/√n) = (9.14 - 10) ÷ (2/√44) = -0.86 ÷ 0.302 = -2.85

Cumulative area of the test statistic = 0.9978

p-value = 2(1 - 0.9978) = 2(0.0022) = 0.0044

(b) The critical value using 0.02 significance level is 2.422. For a two-tailed test, the region of no rejection of the test statistic lies between -2.422 and 2.422.

Conclusion:

Reject the null hypothesis because the test statistic -2.85 falls outside the region bounded by the critical values -2.422 and 2.422.

The population mean of dissolved oxygen content is not equal to 10 mg/L

7 0
3 years ago
Bismuth-210 is an isotope that radioactively decays by about 13% each day, meaning 13% of the remaining Bismuth-210 transforms i
Luden [163]

Answer:

Approximately 76.5 mg.

Step-by-step explanation:

Given,

The initial quantity of the Bismuth-210, P = 233 mg,

Also, the rate of decay per day, r = 13 %

Thus, the quantity of the Bismuth-210 after 8 days would be,

A=P(1-\frac{r}{100})^8

=233(1-\frac{13}{100})^8

=233(1-0.13)^8

=233(0.87)^8

=76.4733194697

\approx 76.5\text{ mg}

3 0
3 years ago
I NEED HELP SOMEONE PLEASE HELP ME
Amanda [17]

Answer:

27.3

Step-by-step explanation:

The base of the triangle is,

√(12²-5²)

= √119 = 10.9

The area of the triangle,

5×10.9/2

= 109/4 = 27.25 ≈ 27.3

Answered by GAUTHMATH

6 0
3 years ago
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