All categories

3 years ago

Math. Find Mid point and fx

Mathematics

1 answer:

Yakvenalex [24]3 years ago

3 0

Answer: Option B.

Step-by-step explanation:

When we have an interval with lower bound m and upper bound M, such that:

m ≤ x ≤ M

The mid-point is:

(m + M)/2

in this case, we have:

m = 22

M = 27

then the mid-point is:

(22 + 27)/2 = 24.5

and we know that f = 7, then:

f*x = f times the mid-point = 7*24.5 = 171.5

The correct option is B.

You might be interested in

It takes a baseball player 16 seconds to round the bases and make it back to home plate home plate if it is 360 feet to go all a

Neko [114]

S= D divided by T
S= 360 divided by 16
S= 22.5

5 0

3 years ago

alpha and beta are the zeros of the polynomial x^2 -(k +6)x +2(2k -1). Find the value of k if alpha + beta = 1/2 alpha beta(ITS

serious [3.7K]

Answer:

$k=\frac{-11}{2}$ .

Step-by-step explanation:

We are given $\alpha$ and $\beta$ are zeros of the polynomial $x^2-(k+6)x+2(2k-1)$ .

We want to find the value of $k$ if $\alpha+\beta=\frac{1}{2}$ .

Lets use veita's formula.

By that formula we have the following equations:

$\alpha+\beta=\frac{-(-(k+6))}{1}$ (-b/a where the quadratic is ax^2+bx+c)

$\alpha \cdot \beta=\frac{2(2k-1)}{1}$ (c/a)

Let's simplify those equations:

$\alpha+\beta=k+6$

$\alpha \cdot \beta=4k-2$

If $\alpha+\beta=k+6$ and $\alpha+\beta=\frac{1}{2}$ , then $k+6=\frac{1}{2}$ .

Let's solve this for k:

Subtract 6 on both sides:

$k=\frac{1}{2}-6$

Find a common denominator:

$k=\frac{1}{2}-\frac{12}{2}$

Simplify:

$k=\frac{-11}{2}$ .

7 0

3 years ago

The KM values for the reaction of chymotrypsin with 2 substrates are given below. Which substrate is likely to give a higher val

Mrrafil [7]

N-acetyltyrosine ethyl ester may likely have a higher Vmax.

<h3>How are the Km and Vmax of an enzyme and substrate related?</h3>

Km is inversely proportional enzyme affinity for substrate. The lower the Km, the higher the enzyme affinity for substrate and vice versa.

Vmax is the maximum velocity of the reaction when the enzyme is fully saturated with substrate.

Based on the Km values, chymotrypsin has higher affinity for N-acetyltyrosine ethyl ester, thus, N-acetyltyrosine ethyl ester may likely have a higher Vmax.

In conclusion, the Vmax is the maximum velocity of an enzyme-catalyzed reaction.

<em>Note that the complete question is given below:</em>

<em>The Km for the reaction of chymotrypsin with N-acetylvaline ethyl ester is 8.8 x 10-2 M, and the Km for the reaction of chymotrypsin with N-acetyltyrosine ethyl ester is 6.6 x 10-4 M.</em>

<em>Which of the following substrates is likely to give a higher value for Vmax?</em>

Learn more about Km and Vmax at: brainly.com/question/16108691

#SPJ1

8 0

1 year ago

Can someone please help me with a histograms quiz!!

viva [34]

What’s the question?

6 0

3 years ago

Evaluate the expression when x= -7.4 and y= -6.3<br>-7y+2x

GenaCL600 [577]

Answer: -29.3

Step-by-step explanation: -7y + 2x

-7(-6.3) + 2(-7.4) = -29.3

5 0

3 years ago

Read 2 more answers

Math. Find Mid point and fx​

Math. Find Mid point and fx