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valina [46]
3 years ago
15

Consider a polynomial p(x) with a degree of 9. What is the largest possible number of x-intercepts and the largest possible numb

er of relative max/min?
Mathematics
1 answer:
tia_tia [17]3 years ago
3 0

Answer:

The largest possible number of x intercept is 9 while the largest possible number of relative max/min is 8

Step-by-step explanation:

For any polynomial of degree n with distinct and real solutions, it can have at most n different x intercepts. This would imply it can have at most 9 distinct real solutions.

It can also have at most n-1 relative max/min in alternating order. This is best illustrated when such polynomial is sketched on a graph.

For example a quadratic expression is a polynomial of degree 2 and has at most 2 distinct solutions and 1 relative max/min.

In this question, for the polynomial, its degree (n) = 9

So it can have at most 9 x intercepts and at most 8 relative max/min.

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3 years ago
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Step-by-step explanation:

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Please help urgent!!! Find the value of x in the triangle shown below!
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Answer:

Step-by-step explanation:

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4 0
2 years ago
Rewrite the following equation in logarithmic form.
zloy xaker [14]

Answer:

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Step-by-step explanation:

  • <em>Use of formula: </em><em>loga (b) = c ⇔ b = a^c</em>

Rewrite the following equation in logarithmic form.   0.25 = 2^-2

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3 0
3 years ago
May someone help me out with this please
Fiesta28 [93]
First we find the mean (average)
(7 + 8 + 9 + 9 + 10 + 11)/6 = 54/6 = 9

now we subtract the mean from every data number....and square it
7 - 9 = -2...-2^2 = 4
8 - 9 = -1...-1^2 = 1
9 - 9 = 0....0^2 = 0
9 - 9 = 0...0^2 = 0
10 - 9 = 1....1^2 = 1
11 - 9 = 2....2^2 = 4

now we find the mean (average) for those numbers
(4 + 1 + 0 + 0 + 1 + 4) / 6 = 10/6 = 1.67...this is the variance

to find the standard deviation, take the sqrt of the variance
sqrt 1.67 = 1.29 <== ur answer
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3 years ago
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