Answer:
see explanation
Step-by-step explanation:
I don't have graphing facilities but can give you the vertex and 1 other point.
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = - 
y = - x² - 2x + 8 ← is in standard form
with a = - 1 and b = - 2 , then
x = -
= - 1
Substitute x = - 1 into the equation for corresponding value of y
y = - (- 1)² - 2(- 1) + 8 = - 1 + 2 + 8 = 9
vertex = (- 1, 9 )
To obtain another point substitute any value for x into the equation
x = 0 : y = 0 - 0 + 8 , then (0, 8 ) is a point on the graph
x = 2 : y = - (2)² - 2(2) + 8 = - 4 - 4 + 8 = 0 then (2, 0 ) is a point on the graph
Step-by-step explanation:
The formula for arc length [for the angle in degrees] is:

here,
= degrees
= radius
using this we'll solve all the parts:
r = 10, n = 20:


from here, it is just simplification:
2 and 360 can be resolved: 360 divided by 2 = 180

10 and 180 can be resolved: 180 divided by 10 = 18

finally, both 20 and 18 are multiples of 2 and can be resolved:

Option (E)
r=3, n=6:


Option (D)
r=4 n=7


Option (C)
r=2 n=x


Option (D)
r=y n=x


Option (E)
Answer:
The other acute angle = 33 1/3°
Step-by-step explanation:
Hard to read the angle measure.
one acute angle = 56 2/3° x = the second acute angle
Find the other acute angles.
The two acute angles sum in a right triangle = 90°
56 2/3° + x° = 90°
x = 90 - 56 2/3
x = 89 3/3° - 56 2/3°
x = 33 1/3°
X+2y=23
X=-2y +23
Plug this in for x in the second equation
5(-2y + 23) + 10y = 55
-10y + 115 + 10y = 55
The -10y + 10y cancel out, so there is no solution
Hope this helps!