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Maurinko [17]
3 years ago
13

Can a negative number have a positive factor?

Mathematics
2 answers:
sertanlavr [38]3 years ago
7 0

Answer:

The laws of multiplication state that when a negative number is multiplied by a positive number, the product will be negative. So, if considering a factor pair of a negative product, one of these factors must be negative and the other factor must be positive.

Gwar [14]3 years ago
5 0
One has to be positive one has to be negative
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Philip and Kevin are hoping to earn enough money to buy concert tickets for a show that costs $225 her concert tickets. Philip a
Zigmanuir [339]

Answer:

Kevin is going to be able to have enough money for the concert the fastest

Philip needs at least 4 weeks

Kevin needs at least 3 weeks

Step-by-step explanation:

<u>Philip</u>

  • $8.75/hour * 6 hours/weekend * 1 weekend/week = $52.5/week
  • $45 saved

Let's call x to the number of weeks Philip needs to reach $225.

52.5*x + 45 = 225

52.5*x = 225 - 45

x = 180/52.5

x = 3.43

He needs at least 4 weeks

<u>Kevin</u>

  • 3 hours/day * $7.5/hour *3 days/week = $67.5/week
  • $30 saved

Let's call y to the number of weeks Kevin needs to reach $225.

67.5*y + 30 = 225

67.5*y = 225 - 30

y = 195/67.5

y = 2.9

He needs at least 3 weeks

6 0
3 years ago
The sum of two integers is 6 and the difference between the numbers is 40. Find the numbers
nevsk [136]


Set up a system of equations.

X+y=6
Y-x =40

Substitution method.

Y=6-x

(6-x)-x =40
6-2x=40
-2x=34
X= -17

Plug it back into the equation.
-17+y=6
Y=33

(-17,33) is one of the possible answers.







8 0
3 years ago
Read 2 more answers
Would these be similar?
const2013 [10]

Hey buddy I am here to help!

Yes these r similar!

Hope this helps!

Plz mark me brainliest!

8 0
2 years ago
Read 2 more answers
The roots of a quadratic equation ax2+bx+c=0 are 3+sqrt2 and 3−sqrt2. Find the values of b and c assuming that a=1.
slamgirl [31]

Answer:

b=-6\\c=7

Step-by-step explanation:

we know that

The general equation of a quadratic function in factored form is equal to

y=a(x-x_1)(x-x_2)

where

a is a coefficient of the leading term

x_1 and x_2 are the roots

we have

a=1\\x_1=3+\sqrt{2}\\x_2=3-\sqrt{2}

substitute

y=(1)(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))

Applying the distributive property convert to expanded form

y=x^2-x(3-\sqrt{2})-x(3+\sqrt{2})+(3+\sqrt{2})(3-\sqrt{2})

y=x^2-(3x-x\sqrt{2})-(3x+x\sqrt{2})+(9-2)

y=x^2-3x+x\sqrt{2}-3x-x\sqrt{2}+7

y=x^2-6x+7

therefore

b=-6\\c=7

7 0
2 years ago
Using the numbers 8,6,4 and 2 write an expression that equals 4
vfiekz [6]
8-(6+2)+4 is how you use those numbers to equal 4
5 0
3 years ago
Read 2 more answers
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