Both expression have the same denominator: 9x²-1. Thus it must not be 0.
9x²-1=(3x-1)(3x+1)=0, resulting x=+-1/3.
Restrictions: x in R\{-1/3, 1/3}
Adding those expressions:
E=(-x-2)/(9x²-1 ) + (-5x+4)/(9x²-1)=
(-x-2-5x+4)/(9x²-1)=(-6x+2)/(9x²-1)=
(-2)(3x-1)/(9x²-1)=-2/(3x+1)
E=-2/(3x+1)
Y - 4x = 7...y = 4x + 7
now sub 4x + 7 in for y in the other equation
2y + 4x = 2
2(4x + 7) + 4x = 2
8x + 14 + 4x = 2
12x = 2 - 14
12x = - 12
x = -1
y - 4x = 7
y - 4(-1) = 7
y + 4 = 7
y = 7 - 4
y = 3
solution is : (-1,3)
Answer:
1) 1:10
2) 150:2
3) 1:3
4) 20hrs : 1hrs
Step-by-step explanation:
Answer:
3-3x and 3
Step-by-step explanation:
f(x) = 3x-3
g(x) = -x
g(f(x)) in your g(x) substitute x with f(x)
g( f(x) ) = g( 3x-3) = -(3x-3) = -3x+3
is the the second choice from top because -3x+3 is the same with 3 -3x
g(f(x)) =3-3x
g(f(0)) always work from inside first, so first find f(0) than g(f(0))
f(0) = f(x=0) = 3*0-3 = -3
Now we do the g(f(0)) = g( -3) is the same as
g(x) except that we substitute x for -3, g(x= -3) = -(-3) =3
g(f(0))=3
*an easier way to find the answer for the second problem would have been that we knew that f(g(x) ) = 3-3x so f(g(0)) =3-3*0 = 3
