The one on the right is correct. please give brainliest.
If the whole diameter of sphere is 6 inch(means radius is 3 inch) & thickness of material is 1 inch, so the radius of the hollow part should be 2 inch (3-1=2)
The total volume of the ball will be;
= Total volume - Volume of hollow part
= 4/3πr³ - 4/3πr³
= 4/3 × 3.14 × (3)³ - 4/3×3.14×(2)³
= 4 × 3.14 × 9 - 4/3 × 3.14 × 8
= 113.04 - 33.52
= 79.52
If the density of the material is 3.25 g/in3, then the density of 79.52 inch³ should be;
= 79.52 × 3.25
= 258.44 g
Now, if there are 8 spheres in one box, the weight if box will be;
= 258.44 × 8
= 2,067.52 g
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Ahh! Finally done with this, if you have any doubt just do ask me :)
The total amount they would get is 93.50$
Answer:
1st Option is correct that is we get circle after slicing a right circular cylinder in small pieces.
Step-by-step explanation:
Given: Jamal Sliced aright circular cylinder into congruent pieces.
To find: Shape of Two-Dimensional plane section obtained after slicing.
We get congruent pieces only when we slice the cylinder parallel to its base at equal heights.
By doing this we get small pieces of cylinders of equal height and equal radius.
Base and top remains same that is circular in shape.
Therefore, 1st Option is correct that is we get circle after slicing a right circular cylinder in small pieces.
This is one easy one
You have to focus on the ml