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2 years ago

Please thank my profile!

Mathematics

2 answers:

Verdich [7]2 years ago

8 0

Okay I will ..thank you

geniusboy [140]2 years ago

3 0

Answer:

Thanks profile

Step-by-step explanation:

You might be interested in

A new phone costs $230 and the sales tax rate is 7%. What is the total cost of the camera after tax?

rosijanka [135]

That's a question about percentage.

One way to represent percentage is using decimal number. In this way, 1 is equivalent to 100% and the other less percentages using numbers between 0 and 1.

Examples:

90% is equivalent to 0,90.
5% is equivalent to 0.05. It's not 0.5 because 0.5 is equivalent to 50%.
13.17% is equivalent to 0.1317.
245% is equivalent to 2.45.

If we want to know the percentage of a number, we should multiplacate the number by the porcentage in the decimal number form.

Examples:

55.90% of 200 is equal to: $200 \times 0.5590 = 111.8$

360% of 88 is equal to: $88\times 3.6 = 316.8$

In our problem, we have a phone with a increase of 7%. To solve that, it's important to perceive that $230 is equal to 100% and with a increase of 7%, we will pay 107%.

107% in the decimal number form is 1.07. With that information, we should multiplicate 1.07 by the original value and we will find the answer.

We know that $230\times 1.07 = 246.1$ , therefore, the total cost of the phone after tax is $246.1.

I hope I've helped. :D

Enjoy your studies. \o/

4 0

3 years ago

Suppose Johnny invests $2,745 into an account, which has been earning interest for many years and he now has a total of $39,974.

Ket [755]

Answer:

i don't understand your question

5 0

3 years ago

Read 2 more answers

Choose one of the factors of 500x3 + 108y18

sammy [17]

Answer:

Option C

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

Step-by-step explanation:

Given: $500x^3 +108y^\left (18\right )$

the common factor from $500x^3$ and $108y^\left (18\right )$ is 4.

therefore, $4\cdot \left ( 125x^3+27y^\left (18\right ) \right )$

$4\cdot \left ( (5x)^3+(3y^6)^3 \right))$

Now, use the formula for above expression: $(a^3+b^3)=(a+b)(a^2-ab+b^2)$

here, $a=5x$ and $b=3y^6$

$( (5x)^3+(3y^6)^3 \right))$ $=(5x+3y^6)(25x^2-15xy^6+9y^12)$

Therefore, we have

$500x^3 +108y^\left (18\right )$ $=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right ) \right )$

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

7 0

3 years ago

Read 2 more answers

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

GrogVix [38]

Answer:

D. f^-1(x) = log2(x -6)
4x^2 -3 . . . . x ≤ 0
B. √(x^5) -3√(x^3) -18√x

Step-by-step explanation:

1. When you replace f(x) by x and x by y, you have

... x = 2^y + 6

The first thing you do is subtract 6; then you take the base-2 logarithm:

... (x -6) = 2^y

... log2(x -6) = y = f^-1(x)

You know that to get the y-term by itself, you must subtract 6. Anything else you do will operate on (x-6). Only answer choice D has that sort of construction.

2. When you swap x and y and solve for y, you have ...

... x = -1/2√(y+3)

... -2x = √(y +3) . . . . . . multiply by -2

... (-2x)^2 = y +3 . . . . . square

... 4x^2 - 3 = y = f^-1(x) . . . . subtract 3

The range of f(x) is (-∞, 0], so that is the domain of f^-1(x). That is, f^-1(x) is defined for x ≤ 0.

3. The product of the two functions is ...

... (x -6)(√x)(x +3) = (√x)(x^2 -3x -18)

<em>Every term</em> will have a factor of √x, and the coefficients will be 1, -3, -18. Only selection B matches those conditions.

7 0

2 years ago

Read 2 more answers

In triangle ABC, P is a centroid on a median AD. If AD=33 and AP>PD find AP

jasenka [17]

Answer:

AP = 22

Step-by-step explanation:

In a triangle, the centroid divides the median in the ratio 2:1.

It is given that AD is the median and AD = 33

It is also given that P is the centroid on the median AD.

Therefore, P divides AD in the ratio 2:1.

$\frac{AP}{PD} =\frac{2}{1}$

AP = 2k and PD = k

AD = 33

AP + PD = 33

2k + k = 33

3k = 33

k = 11

So, AP = 2k = 2(11) = 22

7 0

3 years ago