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Dmitriy789 [7]
3 years ago
5

Consider the following scenarios, where we apply probability to a game of flipping coins. In the game, we flip one coin each rou

nd. The game will not stop until two consecutive heads appear. (a) What is the probability that the game ends by flipping exactly five coins? (b) Given that the game ends after flipping the fifth coin, what is the probability that three heads appear in the sequence?
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
8 0

Answer:

3.125%

0%

Step-by-step explanation:

A regular coin has two sides, meaning that each side has the same probability of landing which is 50%. Therefore, for the game to end exactly on the fifth flip it would need to land 3 times in a row on tails and the last 2 times on heads. Therefore, to get this probability we need to multiply 0.50 (50%) 5 times

0.5 * 0.5 * 0.5 * 0.5 * 0.5 = 0.03125 or 3.125%

Now the probability of three heads appearing in a sequence is 0% because after the second head in a row the game will automatically end.

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Answer:

68/9

Step-by-step explanation:

34 ÷ (14 − 5) × 2

PEMDAS

Parentheses first

34 ÷ (9) × 2

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Which of the following is not a property of a chi-square distribution?
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Answer:

c) Is not a property (hence (d) is not either)

Step-by-step explanation:

Remember that the chi square distribution with k degrees of freedom has this formula

\chi_k^2 = \matchal{N}_1^2 +  \matchal{N}_2^2 + ... + \, \matchal{N}_{k-1}^2 +  \matchal{N}_k^2

Where N₁ , N₂m .... N_k are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.

Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true

The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.

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Answer:

I am not sure how your teacher wanted you to estimate the answer but I solved it for you. Hopefully this helps.

Step-by-step explanation:

7x-y=7

x+2y=6

14x-2y=14

x+2y=6

add both equations

15x=20

x=20/15

x=4/3

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y=14/6

2y=

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3 years ago
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