The inclusion/exclusion principle states that

That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).
Therefore,

will have the most elements when the sets

and

are disjoint, i.e.

, which would mean the most we can can in this case would be

(Note that

denotes the cardinality of the set

.)
The mean is the best measure to summarise the scores.
A LEVER
Its a lever because both sides can be controlled by eachother :)
Ratio 5:4
Total shares = 5+4 = 9
then to find for 1 share = 54/9 = 6
So Sam share = 6 x 5 = 30
Bethan share = 6 x 4 = 24
Poof: 30+24 = 54