Which one is question 20??
Answer:
Here we will use algebra to find three consecutive integers whose sum is 300. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 300. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 300
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 300
3X + 3 = 300
3X + 3 - 3 = 300 - 3
3X = 297
3X/3 = 297/3
X = 99
Which means that the first number is 99, the second number is 99 + 1 and the third number is 99 + 2. Therefore, three consecutive integers that add up to 300 are 99, 100, and 101.
99 + 100 + 101 = 300
We know our answer is correct because 99 + 100 + 101 equals 300 as displayed above.
Step-by-step explanation:
Answer:
2/45
Step-by-step explanation:
We are told that:
A jar contains 2 orange, 4 green, 2 white and 2 black balls.
The total number of balls in the jar is calculated as:
2 orange balls + 4 green balls + 2 white balls + 2 black balls = 10 balls
The probability of drawing an orange ball = P(Orange) = 2/10
The probability of drawing a black ball = P(Black) = 2/10
Therefore, the probability of drawing an orange ball without putting it back, then drawing a black ball is calculated as:
2/10 × 2/9 = 4/90
= 2/45
