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ruslelena [56]
3 years ago
6

For the probability experiment of selecting a chip at random from a bag

Mathematics
1 answer:
andrey2020 [161]3 years ago
5 0
9/100

The chance of selecting a chip at random is equal for all chips, and since there are 9 chips that have a number less than 9, you add their individual probabilities so that 1/100 + 1/100 + 1/100... = 9/100
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Find the 95% confidence interval for estimating the population mean μ
AVprozaik [17]

We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.

Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).

Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.

<h3>Confidence Interval Formula</h3>

The formula for constructing a <u>confidence interval for means</u> is as follows:

  • \displaystyle \overline{x} \pm t^*\big{(}\frac{\sigma}{\sqrt{n} } \big{)}

We are given these variables:

  • \overline{x}=50
  • n=60
  • \sigma=10

Plug these values into the formula for the confidence interval:

  • \displaystyle 50\pm t^* \big{(}\frac{10}{\sqrt{60} } \big{)}

<h3>Finding the Critical Value (t*)</h3>

In order to find t*, we can use this formula:

  • \displaystyle \frac{1-C}{2}=A

Calculating the z-score associated with "A" will give us t*.

So, let's plug in the confidence interval 95% (.95) into the formula:

  • \displaystyle \frac{1-.95}{2}=.025

Use your calculator or a t-table to find the z-score associated with this area under the curve.. you should get:

  • t^*=1.96

<h3>Constructing Confidence Interval</h3>

Now, let's finish the confidence interval we created:

  • \displaystyle 50\pm 1.96 \big{(}\frac{10}{\sqrt{60} } \big{)}

We can calculate the confidence interval, using this formula, to be:

  • \boxed{(47.4697, \ 52.5303)}

<h3>Interpreting the Confidence Interval</h3>

We are 95% confident that the true population mean μ lies between <u>47.4697 and 52.5303</u>.

8 0
1 year ago
You have a recipe for coconut cookies. The recipe makes 20 cookies. You need 100 cookies for a bake sale. Increase the recipe pr
Anon25 [30]

Answer2:

Step-by-step explanation:

1-2

3 0
3 years ago
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What is the domain of the function
Nesterboy [21]

Answer:

hi sh Sheet sh I monorailg Jericho improve Odom Ybor

7 0
3 years ago
Suppose medical records indicate that
Kay [80]

Answer:

Step-by-step explanation:

Let x be the random variable representing the the length of newborn babies (in inches). Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,

z = (x - µ)/σ

Where

x = sample mean

µ = population mean

σ = standard deviation

From the information given,

µ = 20 inches

σ = 2.6 inches

the probability that a given infant is between 14.8 and 25.2 inches long is expressed as

P(14.8 ≤ x ≤ 25.2)

For x = 14.8,

z = (14.8 - 20)/2.6 = - 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.023

For x = 25.2

z = (25.2 - 20)/2.6 = 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.98

Therefore,

P(14.8 ≤ x ≤ 25.2) = 0.98 - 0.23 = 0.75

3 0
3 years ago
Reflect (5,-5) in (a) the x-axis and (b) the y-axis.
astraxan [27]

Answer:

a. (5,5)

b. (-5,-5)

Step-by-step explanation:

reflection over x-axis flips the sign of y-coordinate

reflection over y-axis flips the sign of x-coordinate

6 0
2 years ago
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