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Butoxors [25]
3 years ago
5

The yard care staff can mow 45 lawns in a 10-hour work day. Each of the 9 workers can mow the same number of lawns per hour. How

many lawn can one worker mow per hour
Mathematics
1 answer:
kompoz [17]3 years ago
7 0

If it takes 10 hours for 9 workers to mow 45 lawns, dividing the 45 lawns by 9 we see that in 10 hours one worker can mow 5 lawns. This means that in one hour, a single worker can mow 5/10=1/2 of a lawn

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Based on a poll 62% of internet users are more careful about personal information when using a public wifi hotspot. What is the
Setler79 [48]

Answer:

0.9451

Step-by-step explanation:

Remaining question? <em>"How is the result affected by the additional information that the survey subjects volunteered to​respond?"</em>

Probability that at least 1 user is more careful about personal information when using a public Wi-Fi hot spot is:

P(X≥1) = 1 − P(X<1)

= 1 − P(X=0)

= 1 - [(3,0) (0.62)^0 (1-0.62)^3-0

= 1 - 0.054872

= 0.945128

= 0.9451

Thus, the probability that among three randomly selected Internet users; at least one is more careful about personal information when using a public Wi-Fi hotspot is 0.9451

7 0
3 years ago
Multiply. Write your answer in scientific notation. (2 x 10^7) (1 x 10^7)
loris [4]
2 x 10exponent 14 I think
7 0
3 years ago
Find the value of x that makes each sentence true.
ki77a [65]

Answer:

51/25 and 27/4

Step-by-step explanation:

distributing and dividing both sides by coefficient of x

8 0
3 years ago
Read 2 more answers
Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 mill
abruzzese [7]

Answer:

V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794 million per year

Step-by-step explanation:

Given that oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 million barrels of oil in the well; six years later 1,500,000 barrels remain.

i.e. if V stands for volume of oil, then

V' =kV\\dv/V= kdt\\ln V = kt+C\\V = Ae^{kt}

To find A and k

V(0) = A = 3 million

Hence V = 3e^{kt}

V(6) = 1.5

i.e. 1.5 = 3e^{6k}\\ln 1.5 =ln 3 +6k\\k = -0.11552

V(t) = 3e^{-0.11552t}

a) Using the above value of k , we have

V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794 million per year.

4 0
4 years ago
What is the value of x in the equation below?<br> -3-(-8)-(-2) = x<br> O-13<br> O9<br> O 3<br> O 7
posledela

Answer:

7

Step-by-step explanation:

4 0
3 years ago
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