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Pavlova-9 [17]
2 years ago
8

Multiply. Write your answer in scientific notation. (2 x 10^7) (1 x 10^7)

Mathematics
1 answer:
loris [4]2 years ago
7 0
2 x 10exponent 14 I think
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Solve 12x-5>-2 please
Stells [14]

Answer:

x >  \frac{1}{4}

Step-by-step explanation:

12x - 5 >  - 2

Lets add +5 in both the sides.

=  > 12x - 5 + 5 >  - 2 + 5

=  > 12x > 3

Now lets divide 12 on both the sides.

=  >  \frac{12x}{12}  >  \frac{3}{12}

=  > x >  \frac{1}{4}

8 0
3 years ago
A family plans to water ski at a local lake. If the temperature outside is 30 degrees C, what is the temperature in degrees F? U
Sphinxa [80]
30 degrees C = 86 degrees F
8 0
3 years ago
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Solve for c 8/3c -2= 2/3c-12
Anna [14]

Answer: C = -5

Step-by-step explanation:

You have to add two on both sides and the remove 2/3 on both sides. Hope this helps

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3 years ago
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To prove :One plus cot square theta into tan theta by sec square theta = cot theta
pickupchik [31]

we are given

\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)

We will simplify left side and make it equal to right side

Left side:

\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)}

we can use trigonometric identity

1+cot^2(\theta)=csc^2(\theta)

we can replace it

\frac{(csc^2(\theta))*tan(\theta)}{sec^2(\theta)}

we know that

csc=1/sin and sec=1/cos

so, we can replace it

and we get

\frac{cos^2(\theta)tan(\theta)}{sin^2(\theta)}

now, we know that

tan =sin/cos

\frac{cos^2(\theta)*sin(\theta)}{sin^2(\theta)*cos(\theta)}

we can simplify it

and we get

\frac{cos(\theta)}{sin(\theta)}

we can also write it as

=cot(\theta)

Right Side:

cot(\theta)

we can see that

left side = right side

so,

\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)......Answer

6 0
3 years ago
Check the obtained values of 4s²+12s=-9​
marta [7]

\\ \bull\tt\looparrowright 4s^2+12s=-9

\\ \bull\tt\looparrowright 4s^2+12s+9=0

\\ \bull\tt\looparrowright 4s^2+6s+6s+9=0

\\ \bull\tt\looparrowright 2s(2s+6)+3(2s+3)=0

\\ \bull\tt\looparrowright (2s+6)(2s+3)=3

\\ \bull\tt\looparrowright s=-2\:or\:s=\dfrac{-3}{2}

6 0
2 years ago
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