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drek231 [11]
3 years ago
6

There I Need help with it c:

Mathematics
2 answers:
zaharov [31]3 years ago
8 0
1-Linda
2-Kevin
3-Kevin
4-Kevin

Sorrry im late xD
Gnesinka [82]3 years ago
7 0
1.a
2.b
3.b
4.b
hope i helped out good luck:)
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Divide 63.5 ÷ 0.25 round the quotient to the nearest ten-thousandth
hram777 [196]

Answer:

254

Step-by-step explanation:

63.5 ÷ 0.25 =

= 63.5 ÷ 1/4

= 63.5 × 4

= 254

Answer: 254.

8 0
2 years ago
Solve for x<br><br> 7/8 of x is 14
SVEN [57.7K]

7÷8 of x = 14

  1. 8/7×7/8 of x=14×8/7
  2. x=16
8 0
1 year ago
Read 2 more answers
Help show work<br> Thank you
Anika [276]
1.) v=(l)(w)(h)
V=(9)(9)(9)
V=(81)(9)
V=729in^3

2.) (I forget if this is the real equation to this but this would give you the same answer)

V=(l)(w)(h)
————
2
V=(8)(6)(12)
————-
2
V=576/2

V=288cm^3
7 0
3 years ago
The box plots show the weights, in pounds, of the dogs in two different animal shelters.
zimovet [89]

*see attachment below for the box plots that is being referred to

Answer:

*The median weight for shelter A is greater than that for shelter B

*The data for shelter B are a symmetric data set

Step-by-step explanation:

Let's take each stated option and examine the box plot to see which is TRUE or NOT.

OPTION 1: "The median weight for shelter A is greater than that for shelter B."

The median for shelter A = 21,

Median for shelter B = 18

Median weight for shelter A (21) is greater than that for shelter B.

This statement in this option is TRUE.

OPTION 2: "The median weight for shelter B is greater than that for shelter A."

Median for B (18) < median of A (21)

This statement in option is NOT TRUE.

OPTION 3: "The data for shelter A are a symmetric data set."

This is NOT TRUE because the length of both whiskers are unequal and also, the box is not divided equally. One side is longer than the other.

OPTION 4: "The data for shelter B are a symmetric data set."

This is TRUE because the length of both whiskers are relatively equal, and also, the rectangular box is divided equally.

OPTION 5: "The interquartile range for shelter A is 8"

This is NOT TRUE.

IQR = Q3-Q1

IQR for shelter A is approximately  = 28-17 = 11

5 0
3 years ago
Find the length of the third side. If necessary, round to the nearest tenth
Rina8888 [55]

Answer:

x=14.28

Step-by-step explanation:

24^2+x^2=28^2, Pythagorean theorem

x^2=28^2-24^2

x^2=(28+24)(28-24)

x^2=52*4

x^2=204

x is around 14.28

3 0
2 years ago
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