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drek231 [11]
4 years ago
6

There I Need help with it c:

Mathematics
2 answers:
zaharov [31]4 years ago
8 0
1-Linda
2-Kevin
3-Kevin
4-Kevin

Sorrry im late xD
Gnesinka [82]4 years ago
7 0
1.a
2.b
3.b
4.b
hope i helped out good luck:)
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Differences in linear and quadratic equations
BabaBlast [244]

Answer:

linear equation has two variables doesn't involve any power

quadratic equation involves one of the variables raised to the second power.

Step-by-step explanation:

A <u>linear equation</u> in two variables doesn't involve any power higher than one for either variable. It has the general form Ax + By + C = 0, where A, B and C are constants. ... A <u>quadratic equation</u>, on the other hand, involves one of the variables raised to the second power.

7 0
3 years ago
Simplify each expression using the laws of exponents. No negative exponents should be in your final answer. (On the image attach
Cloud [144]

Answer:

<em>Answer</em><em> </em><em>is</em><em> </em><em>given below with explanations</em><em>. </em>

Step-by-step explanation:

by \: simplifying \: the \: given \: expression \: using \:  \\ law \: of \: exponents \: we \: get \\  \frac{15 {x}^{15}  {y}^{ - 3}  {z}^{4} }{18 {x}^{18}  { {y}^{4}  {z}^{ - 4} }^{} }  \\   = \frac{5  \: {x}^{ - 3}  {y}^{ - 7} {z}^{8}  }{6}  \\ we \: may \: also \: write \: as \\  =  \frac{5 {z}^{8} }{6 {x}^{3}  {y}^{7} }

formulae \: used  \ \: : \\  \frac{ {x}^{m} }{ { {x}^{n} }^{} }  =  {x}^{m - n}  \:  \:  \: and \\  {x}^{ - m}  =  \frac{1}{ {x}^{m} }

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

5 0
3 years ago
Read 2 more answers
H E L P M E P L E A S E !!!
Art [367]

Given:

The table of data values.

To find:

What is the percentage of 10th grade students are in 2 clubs.

Solution:

From the given table it is clear that the number of 10th grade students are in 2 clubs is 12.

Total number of students in 10th grade is:

125+12+15=152

Now, the percentage of 10th grade students are in 2 clubs is:

\text{Required percentage}=\dfrac{\text{Number of 10th grade students are in 2 clubs}}{\text{Total number of students in 10th grade}}\times 100

\text{Required percentage}=\dfrac{12}{152}\times 100

\text{Required percentage}=\dfrac{1200}{152}

\text{Required percentage}\approx 7.89\%

Therefore, the percentage of 10th grade students are in 2 clubs is 7.89%.

5 0
3 years ago
LIVE
zzz [600]

Answer

Step-by-step explanation:

8 0
3 years ago
1/8 times what equals one
Dvinal [7]
8/1 × 1/8= 1 because 1/8's reciprocal is 8/1
4 0
3 years ago
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