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umka21 [38]
2 years ago
5

What is the base of a parallelogram if the height is 6 5/8 feet and area 26 1/2 square feet?​

Mathematics
1 answer:
Natali [406]2 years ago
3 0

Area of a parallelogram is base x height so 25 1/2 = base x 6 5/8 so to find x you would divide each side by 6 5/8 so the base would be 2 26/53 square feet

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scoray [572]

Answer:

31/40

Step-by-step explanation:

Given that:

Fraction of the trail walked intulally = 9/10

Fraction of the trail walked back = 1/8 before stopping to rest

His current distance from the beginning :

Distance walked initially - distance walked back

9/10 - 1/8

The L. C. M of 10 and 8 = 80

Hence,

9/10 - 1/8

= (72 - 10) / 80

= 62 / 80

= 31 / 40

Hence, his rest point or position is 31/40 from the beginning of the trail

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3 years ago
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Step-by-step explanation:

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2 years ago
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8 0
3 years ago
What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16
kicyunya [14]

Answer:

y=\pm i \sqrt{7}

Step-by-step explanation:

Given equation is \frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

Factor denominators then solve by making denominators equal

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

y\left(y+4\right)-4\left(y-4\right)=9

y^2+4y-4y+16=9

y^2=9-16

y^2=-7

take squar root of both sides

y=\pm \sqrt{-7}

y=\pm i \sqrt{7}

Hence final answer is y=\pm i \sqrt{7}.

7 0
3 years ago
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