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Alex787 [66]
4 years ago
5

Ellen now has $125. how much would she have after 8 years if she leaves it invested at 8.5% with annual compounding?

Mathematics
1 answer:
liraira [26]4 years ago
3 0

We know the formula for compound interest as

A=P(1+\frac{r}{n})^{nt}

Now, we have been given that Ellen has $125. It means we have

P = $125

From the given directions, we have

r=0.085\\
t=8\\
n=1

On substituting these values in the above mentioned formula, we have

A=125(1+\frac{0.085}{1})^{1\times 8}\\
\\
A=\$240.08

Therefore, Ellen would have $240.08 after 8 years.


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Step-by-step explanation:

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What is the equation in point-slope form of a line that passes through the points (7, −8) and (−4, 6) ?
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The slope-point form:

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If the numerator of a fraction is increased by six, the value of the fraction will increase by one. If the denominator of the or
Alchen [17]

Answer:

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Step-by-step explanation:

Let \dfrac{a}{b} be the original fraction.

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\dfrac{a+6}{b}=\dfrac{a}{b}+1

If the denominator of the original fraction is increased by 36, the value of the original fraction will decrease by one. Hence,

\dfrac{a}{b+36}=\dfrac{a}{b}-1

Add these two equalities:

\dfrac{a+6}{b}+\dfrac{a}{b+36}=\dfrac{a}{b}+1+\dfrac{a}{b}-1\\ \\\dfrac{a+6}{b}+\dfrac{a}{b+36}=2\dfrac{a}{b}\\ \\\dfrac{a}{b+36}=\dfrac{2a-(a+6)}{b}\\ \\\dfrac{a}{b+36}=\dfrac{a-6}{b}\\ \\ab=(a-6)(b+36)\\ \\ab=ab+36a-6b-216\\ \\36a-6b-216=0\\ \\6a-b-36=0\\ \\b=6a-36

Substitute it into the first equation:

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\dfrac{7}{6}

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4 years ago
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Step-by-step explanation:

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