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dangina [55]
3 years ago
6

What is the equation in point-slope form of a line that passes through the points (7, −8) and (−4, 6) ?

Mathematics
1 answer:
nika2105 [10]3 years ago
7 0

The slope-point form:

y-y_1=m(x-x_1)

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (7, -8) and (-4, 6). Substitute:

m=\dfrac{6-(-8)}{-4-7}=\dfrac{14}{-11}=-\dfrac{14}{11}\\\\y-6=-\dfrac{14}{11}(x-(-4))\\\\\boxed{y-6=-\dfrac{14}{11}(x+4)}

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1/7 x X =1 <br> X x 1/11=1<br> 1 divided by 1/5=
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Answer:

  1. x = 7
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Step-by-step explanation:

\frac{1}{7}  \times x = 1

7 \times  \frac{1}{7} x = 7 \times 1

7 \times  \frac{1}{7} x = 7

\boxed{\green{x = 7}}

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x \times  \frac{1}{11}  = 1

\frac{1}{11} x  = 1

11 \times  \frac{1}{11} x = 11 \times 1

11 \times  \frac{1}{11} x = 11

\boxed{\green{x = 11}}

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1 \div  \frac{1}{5}  = 1 \times  \frac{5}{1}

1 \times 5

\boxed{\green{= 5}}

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