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dangina [55]
3 years ago
6

What is the equation in point-slope form of a line that passes through the points (7, −8) and (−4, 6) ?

Mathematics
1 answer:
nika2105 [10]3 years ago
7 0

The slope-point form:

y-y_1=m(x-x_1)

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (7, -8) and (-4, 6). Substitute:

m=\dfrac{6-(-8)}{-4-7}=\dfrac{14}{-11}=-\dfrac{14}{11}\\\\y-6=-\dfrac{14}{11}(x-(-4))\\\\\boxed{y-6=-\dfrac{14}{11}(x+4)}

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Choose 3 values that would make this inequality true. 8n + 4 ≤ 28 <br><br> Choices:3,6,13,2,5,14,1
Lelu [443]

Answer:

1,2,3

Step-by-step explanation:

1*8=8+4+12<28

2*8=16+4=20<28

3*8=24+4=28=28

6 0
2 years ago
Nd the 52nd term and the term named in the problem <br>40, 140, 240, 340, ...<br>Find a 32​
Galina-37 [17]

Answer:

5140 and 3140

Step-by-step explanation:

Note there is a common difference d between consecutive terms in the sequence, that is

d = 140 - 40 = 240 - 140 = 340 - 240 = 100

This indicates the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 40 and d = 100, thus

a_{52} = 40 + (51 × 100) = 40 + 5100 = 5140

a_{32} = 40 + (31 × 100) = 40 + 3100 = 3140

5 0
3 years ago
ANSWER PLLLLEEEEAAASSSEEE
Whitepunk [10]

Answer:

30%

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Madame Pickney has a rather extensive art collection and the overall value of her collection has been increasing each year. Thre
Anettt [7]

Answer:

Value = 500000 × (1.1^n)

$1,296,871

Step-by-step explanation:

a = 500000

r = 550000 ÷ 500000 = 1.1

1st term is the initial year:

n years after that is the "n+1"th term

Value = 500000 × (1.1^n)

n = 10

500000(1.1¹⁰)

1,296,871.23005

3 0
3 years ago
Read 2 more answers
For the piecewise function, find the values h( - 6), h(0), h(5), and h(9).- 5x – 13, for x &lt; -3h(x) = { 5, for - 35x&lt;5for
sleet_krkn [62]

Given the piecewise function h(x):

h(x)=\begin{cases}-5x-13,x

-When x is less than "-3", h(x)=-5x-13

-When x is between -3 and 5, h(x)=5

-When x is greater than or equal to 5, h(x)=x+1

1) For h(-6), this notation indicates that you have to determine the value of h(x) when x=-6

-6 is less than -3, which means that for this value of x, the function has the following shape

h(x)=-5x-13

Replace the expression with x=-6 and calculate the corresponding value of x:

\begin{gathered} h(-6)=-5(-6)-13 \\ h(-6)=30-13 \\ h(-6)=17 \end{gathered}

2) For h(0), you have to determine the value of h(x) when x=0. Zero is between -3 and 5, for this value of x, the function h(x) has the following shape:

h(x)=5

This equation represents a horizontal line, which means that for every value within the interval of definition -3≤x<5, the function always has the same value h(x)=5

We can conclude that:

h(0)=5

3) For h(5), you have to determine the value of h(x) for x=5, for values of x greater than or equal to 5, h(x) has the following shape:

h(x)=x+1

Replace the expression with x=5 and calculate the corresponding value of h(x):

\begin{gathered} h(5)=5+1 \\ h(5)=6 \end{gathered}

4) For h(9), you have to determine the value of h(x) when x=9, 9 is greater than 5, for this value of x, the function has the following shape:

h(x)=x+1

Replace the expression with x=9, and calculate the corresponding value of h(x):

\begin{gathered} h(9)=9+1 \\ h(9)=10 \end{gathered}

So, to sum up:

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5 0
1 year ago
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