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2 years ago

Can someone help me with this I am not the best at math

Mathematics

1 answer:

mamaluj [8]2 years ago

5 0

4.)

A.)

P = 140

i = 0.05

B.)

140(1.05)^t

C.)

0 = 140

10 = 228.05

5.)

A.) The y-intercept is how much the cell phone cost to purchase.

B.) V means value, t meaning years was replaced by 4, and 31.25 is how much it's worth at that time.

C.) The graph is decreasing, and the value goes down with time.

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Please help. Will mark brainliest if correct. ( links will be banned)

Hatshy [7]

Answer:

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Step-by-step explanation:

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2 years ago

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ABCD is a rhombus find the measures of <2 and <3, if m <1=22

Harrizon [31]

Angle 2 = 22 degrees (that line is dividing that angle into 1 & 2 equivalently)

Angle 3 = 90 degrees.

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2 years ago

HELP ME PLEASE. explain step by step

andrew11 [14]

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3 years ago

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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

irga5000 [103]

Answer:

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

$y = -16x^2 + 177x + 98$

It hits the ground when $y = 0$ , so we have to find x for which $y = 0$ , which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$y = -16x^2 + 177x + 98$

$-16x^2 + 177x + 98 = 0$

$a = -16, b = 177, c = 98$

$\bigtriangleup = 177^{2} - 4(-16)(98) = 37601$

$x_{1} = \frac{-177 + \sqrt{37601}}{2*(-16)} = -0.53$

$x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59$

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

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2 years ago

A random sample of 20 purchases showed the sample mean of $48.77 and the sample standard deviation s is $17.58. How large is the

laila [671]

Answer:

Step-by-step explanation:

Given data

Sample Mean (M): $48.77

Sample Size (n): 20

Standard Deviation (σ) : $17.58

Confidence Level: 80%

we know that z*-Values for 80% Confidence Levels is 1.28

the expression for margin of error is given bellow\

MOE= z*σ/√n

We can now substitute into the expression and solve for the MOE as

MOE= 1.28*17.58/√20

MOE= 22.502/4.47

MOE= 5.03

The margin of error for a 80 % confidence interval is $5.03

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2 years ago