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MakcuM [25]
3 years ago
12

Can someone help me with this I am not the best at math

Mathematics
1 answer:
mamaluj [8]3 years ago
5 0

4.)

A.)

P = 140

i = 0.05

B.)

140(1.05)^t

C.)

0 = 140

10 = 228.05

5.)

A.) The y-intercept is how much the cell phone cost to purchase.

B.) V means value, t meaning years was replaced by 4, and 31.25 is how much it's worth at that time.

C.) The graph is decreasing, and the value goes down with time.

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Find the values of x and y. ​
Sedaia [141]

Answer:Input : A = 12, B = 8

Output : X = 2, Y = 10

Input : A = 12, B = 9

Output : -1

Step-by-step explanation:

7 0
2 years ago
If ∆ABC congruent ∆DEF, which of the following can you NOT conclude as being true?
enyata [817]

Answer:

I believe the answer would be C (sorry i messed uo the first time)

4 0
2 years ago
Read 2 more answers
1. 3x + 6y = 3 and 7x + 3y = 7<br>ons for bo​
sweet-ann [11.9K]

Answer:

(1,0)

Step-by-step explanation:

3x + 6y = 3

7x + 3y = 7

Multiply the second equation by -2

-2( 7x + 3y = 7)

-14x -6y = -14

Add this to the first equation to eliminate y

3x + 6y = 3

-14x -6y = -14

--------------------

-11 x = -11

Divide by -11

x = 1

Now find y

3x + 6y = 3

3 +6y = 3

Subtract 3 from each side

6y = 0

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3 0
3 years ago
Read 2 more answers
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

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7 0
3 years ago
A certain company manufactures skateboards and rollerskates. It takes them 2 units of labor and 1 unit of materials to produce a
Alisiya [41]

Answer: The company should produce 7 skateboards and 16 rollerskates in order to maximize profit.

Step-by-step explanation: Let the skateboards be represented by s and the rollerskates be represented by r. The available amount of labour is 30 units, and to produce a skateboard requires 2 units of labor while to produce a rollerskate requires 1 unit. This can be expressed as follows;

2s + r = 30 ------(1)

Also there are 40 units of materials available, and to produce a skateboard requires 1 unit while a rollerskate requires 2 units. This too can be expressed as follows;

s + 2r = 40 ------(2)

With the pair of simultaneous equations we can now solve for both variables by using the substitution method as follows;

In equation (1), let r = 30 - 2s

Substitute for r into equation (2)

s + 2(30 - 2s) = 40

s + 60 - 4s = 40

Collect like terms,

s - 4s = 40 - 60

-3s = -20

Divide both sides of the equation by -3

s = 6.67

(Rounded up to the nearest whole number, s = 7)

Substitute for the value of s into equation (1)

2s + r = 30

2(7) + r = 30

14 + r = 30

Subtract 14 from both sides of the equation

r = 16

Therefore in order to maximize profit, the company should produce 7 skateboards and 16 rollerskates.

6 0
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