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3 years ago

I don't know who needs to hear this but I wanted to hopefully reach out to someone.

Mathematics

2 answers:

Eva8 [605]3 years ago

8 0

Answer:

thank you for reaching out to help people that is going through a hard time

OlgaM077 [116]3 years ago

7 0

Answer:

thx for this,i really needed it. :)

Step-by-step explanation:

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Can someone help me on this and thanks

Natasha_Volkova [10]

Answer: False

Step-by-step explanation:

Although it does go through y= -4

Doing Rise/Run we go up 2 and and over to the right 3 and see it does not cross through the point.

5 0

3 years ago

Solve the inequality for x and identify the graph of its solution.

bixtya [17]

Answer:

Step-by-step explanation:

^^^

5 0

2 years ago

The angles of a triangles are x°, 3x° and 30°. When asked to solve for x, Alvi shows the work in post-it A below. Brian shows th

klasskru [66]

Answer:

See explanation

Step-by-step explanation:

OK. Alvi is incorrect because he didn't add the measures of all 3 angles of the triangle, whereas Brian did. So, Brian is correct and Alvi needs to work on that kind of problem.

8 0

3 years ago

My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the

AVprozaik [17]

Answer:

a) $n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

b) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by: