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3 years ago

12

Find the value of X

2 answers:

muminat3 years ago

6 0

Answer:

X

Step-by-step explanation:

no problem to solve hahahahahahaha

NemiM [27]3 years ago

5 0

Answer :The answer is X.

Your welcome

You might be interested in

Write the explicit rule for the arithmetic sequence

blagie [28]

Given that:
a1=27, an=(an-1)+4
the second term will be:
a2=a1+4
a2=27+4=31
The explicit formula for arithmetic sequence is given by:
an=a+(n-1)d
where:
a= first term
d=common difference
n=nth term
from the information given:
a=27
d=31-27=4
thus the explicit formula will be:
an=27+(n-1)4
an=27+4n-4
an=23+4n

Answer: an=23+4n

6 0

3 years ago

The hypotenuse of a right triangle is 1 centimeter longer than one side and 4 centimeters longer than three times the other side

snow_tiger [21]

Answer:

$Hypotenuse = 25cm$

$Opposite = 24cm$

$Adjacent = 7cm$

Step-by-step explanation:

Represent:

The opposite with a
The adjacent with b
The hypotenuse with c

Given that:

$c = 1 + a$

$c = 4 + 3b$

Required

Solve for a, b and c

$c = c$

So, we have:

$1 + a = 4 + 3b$

Subtract 1 from both sides

$a = 4 -1 + 3b$

$a = 3 + 3b$

Apply Pythagoras Theorem

$c^2 = a^2 + b^2$

Substitute 3 + 3b for a and 4 + 3b for c

$(4 + 3b)^2 = (3 + 3b)^2 + b^2$

Open brackets

$16 + 12b+12b+9b^2 = 9 + 9b+9b+9b^2 +b^2$

$16 + 24b+9b^2 = 9 + 18b+10b^2$

Collect Like Terms

$10b^2 - 9b^2 + 18b - 24b + 9 - 16 = 0$

$b^2 - 6b -7 = 0$

Expand

$b^2 +b-7b-7=0$

Factorize:

$b(b+1)-7(b+1) =0$

$(b-7)(b+1) = 0$

Split:

$b - 7 = 0\ or\ b+1=0$

$b = 7\ or\ b=-1$

But the adjacent of a triangle can't have a negative measurement.

So:

$b = 7$

Recall that:

$c = 4 + 3b$

$a = 3 + 3b$

Substitute 7 for b in the above expressions

$c = 4 + 3 * 7$

$c = 4 + 21$

$c = 25$

$a = 3 + 3 * 7$

$a = 3 + 21$

$a = 24$

Hence, the dimensions of the triangle are:

$Hypotenuse = 25cm$

$Opposite = 24cm$

$Adjacent = 7cm$

5 0

3 years ago

Please help me i need it :)

Musya8 [376]

Answer:

I think the incenter of LO is 27 like ML

Step-by-step explanation:

because LO is almost the same of ML

5 0

3 years ago

A polynomial has zeros x=0, x= -3, X = 4. What are some possible factored equations for this fourth degree polynomial.

kati45 [8]

Answer:

$x^{2} (x + 3)(x - 4)$

Step-by-step explanation:

You can multiply this out to get the full equations.

It's to the 4th degree so the x on the outside has to be squared to add the fourth degree.

To get other zeros:

x + 3 = 0

x = -3

x - 4 = 0

x = 4

Hope this helped. :0)

5 0

3 years ago

What would the variables for a and b be? 3/x + 5/x^2 = (ax+b)/x^2

allsm [11]

Answer:

a=3,b=5

Step-by-step explanation:

$\frac{3}{x} + \frac{5}{ {x}^{2} } \\ = \frac{3x}{ {x}^{2} } + \frac{5}{ {x}^{2} } \\ = \frac{3x + 5}{ {x}^{2} }$

so as you got it:

$\frac{(ax + b)}{ {x}^{2} } = \frac{3x + 5}{ {x}^{2} } \\ a = 3 \\ b = 5$

4 0

3 years ago