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3 years ago

What is the general form of the equation of a circle with its center at (-2,1) and passing though (-4,1) ?

1 answer:

4 0

Equation is :( x + 2 )² + ( y - 1 )² = r²( - 4 + 2 )² + ( 1 - 1 )² = r²4 = r², than we will plug in to a formula:( x + 2 )² + ( y - 1 )² = 4x² + 4 x + 4 + y² - 2 y +1 = 4x² + y² + 4 x - 2 y + 1 = 0
the answer is : <span>x2 + y2 + 4x − 2y + 1 = 0 </span>

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(14) Geometry pls help<br><br> Check my ans<br><br> I really dont know on this one

mestny [16]

Close. It's actually choice D) 7 < n < 17
The value n must be less than 5+12 = 17. If its equal to 17 or larger, then a triangle isn't possible.

3 0

4 years ago

Make P the subject.<br> Q = 3P + 2

Ne4ueva [31]

Answer:

P = $\frac{Q-2}{3}$

Step-by-step explanation:

Q = 3P + 2 ( subtract 2 from both sides )

Q - 2 = 3P ( isolate P by dividing both sides by 3 )

$\frac{Q-2}{3}$ = P

4 0

2 years ago

I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct

joja [24]

*If you need me to do #5, DM me!

3. The area of a triangle can be given by (just plug and chug as always):
$A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2$
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
$A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2$
$A_r = bh = 12(8) = 96m^2$
Now we just add them:
$96+12 = 108m^2$

So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:
$A_t = \frac{1}{2}bh$
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
$A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2$
Multiply by 4 to get total area:
$6.25*4 = 25cm^2$

So, the area of the given rhombus is 25cm².

8 0

4 years ago

A line y=mx+b is translated using the vector . Write the equation of the translated line. What is the value of the y -intercept?

schepotkina [342]

The found value are-

Equation of the translated line: y = mx − am + 2b.
The value of the y -intercept: 2b − am.

<h3>What is general form of straight line?</h3>

A straight line's general equation is y = mx + c, in which m is the gradient and y = c is the value at which the line intersects the y-axis. This number c is known as the y-axis intercept.

Now, as per the given question;

The general equation of the line is given as;

y = mx + b

Each point (x,y) of the line is moved to the point (x+a, y+b) by the translation:

(x,y) ---> (x+a, y+b)

We find the original line's x and y intercepts:

Put y=0 in general equation of the line

⇒mx+b = 0

⇒x = −b/m

When, x=0

⇒y = m⋅0 + b

⇒ y = b

A, (0,b) and B( -b/m, 0)

We find the translational coordinates of the points A,B:

A(0,b) ---> A′ (0+a,b+b)

A(0,b) ---> A′ (a,2b)

And,

B( -b/m, 0) ----> B'( -b/m + a, 0 + b)

B( -b/m, 0) ----> B'( -b/m + a, b)

To find the equation of the line's translation, we use the points A and B ′:

m' = (2b - b)/[a - (-b/m +a)]

m' = b/(b/m)

m' =m

And,

y−yA' = m' (x−xA')

y−2b=m(x−a)

y=mx−am+2b

The translation of the line's x and y intercepts are:

Put x=0

⇒y = m⋅0−am+2b

⇒y = 2b−am

And, put y=0

⇒0 = mx−am+2b

⇒x = a - (2b/m)

Therefore, the equation of the translate line is found to be y = mx − am + 2b.

And, the value of the y-intercept is found to be 2b−am.

To know more about the general form of straight line, here

brainly.com/question/4227212

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3 0

1 year ago

if there are 15 puppies 12 kittens and 6 rabbits in a pet store than what animals are in a 5 to 2 ratio

IrinaK [193]

Puppies and kittens.

7 0

4 years ago