Question

I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct

Answer 1

*If you need me to do #5, DM me!

3. The area of a triangle can be given by (just plug and chug as always):
$A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2$
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
$A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2$
$A_r = bh = 12(8) = 96m^2$
Now we just add them:
$96+12 = 108m^2$

So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:
$A_t = \frac{1}{2}bh$
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
$A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2$
Multiply by 4 to get total area:
$6.25*4 = 25cm^2$

So, the area of the given rhombus is 25cm².