Simplify radical 5 times 8 + 3 with a radical of 6

Mathematics

1 answer:

abruzzese [7]3 years ago

5 0

Answer:

3 $\sqrt{30} a+8 \sqrt{5}$

Step-by-step explanation:

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The Answer to This Question

xenn [34]

Recall the Trigonometric Ratio below:

$\tt{ \large{sin \theta = \frac{opposite}{hypotenuse} } }\\ \tt{\large{cos \theta = \frac{adjacent}{hypotenuse} }} \\ \tt{ \large{tan \theta = \frac{opposite}{adjacent} }}$

For csc, sec and cot - they are reciprocal of sin,cos and tan.

$\tt{ \large{csc \theta = \frac{1}{sin \theta} } }\\ \tt{ \large{sec \theta = \frac{1}{cos \theta} }} \\ \tt{ \large{cot \theta = \frac{1}{tan \theta} }}$

What we know now is our hypotenuse, adjacent and opposite length.

hypotenuse = 15
opposite = 12
adjacent = 9

Therefore,

$\large{sin \theta = \frac{12}{15} \longrightarrow \frac{4}{5} } \\ \large{cos \theta = \frac{9}{15} \longrightarrow \frac{3}{5} } \\ \large{ tan \theta = \frac{12}{9} \longrightarrow \frac{4}{3} }$ As for the reciprocal of three trigonometric ratio. We just swap the numerator and denominator.

$\large{csc \theta = \frac{15}{12} \longrightarrow \frac{5}{4} } \\ \large{sec \theta = \frac{15}{9} \longrightarrow \frac{5}{3} } \\ \large{cot \theta = \frac{9}{12} \longrightarrow \frac{3}{4} }$