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Tamiku [17]
3 years ago
11

Find the lowest value of the set of data this box-and-whisker plot represents.

Mathematics
2 answers:
wel3 years ago
5 0

Answer:

12

Step-by-step explanation:

its the lowest #

Delvig [45]3 years ago
4 0
The lowest set of data is 12
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Nadir saves $1 the first day of a month, $2 the second day, $4 the third day, and so on. He continues to double his savings each
Leto [7]

The answer is $16,384. If this helps you please make it brainliest as it helps me out.

2

4

8

16

32

64

128

256

512

1024

2048

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8,192

16,384

6 0
3 years ago
4. Find the solution to each equation mentally.
White raven [17]
A, 10. b,-300. c, -1. d, -3567.
youre basically looking for the number that gets you to the other number. how far away from 30 is 40? 10. how far is 500 from 200? 300, but in the other direction so its negative. and for D since the final number is 0 just use the same number but flip the sign
5 0
3 years ago
Read 2 more answers
BRAINLIEST ANSWERS ONLY.
mars1129 [50]

Answer:

Heyy

Step-by-step explanation:

△ABC is a right angled triangle and right angle at B

sinA=

AC

BC

, cosA=

AC

AB

⟹sinA+cosA=

AC

BC

+

AC

AB

=

AC

BC+AB

[We know that sum of two sides of a triangle is greater than the third side]

⟹sinA+cosA>

AC

AC

=1

Hence, sinA+cosA>1

4 0
2 years ago
Which of these best describes d, the diameter of a circle?
oee [108]

Answer:

B).

Step-by-step explanation:

Answer explantion

A) the ratio of the circumference of the circle to Pi: false

B) exactly 3.14 :true

C) the ratio of the diameter of a circle to Pi:false

D) the square of the circumference of a circle:false

6 0
3 years ago
Y=x^2-6x-16 in vertex form
satela [25.4K]

Answer:

y=(x-3)^{2} -25

Step-by-step explanation:

The standard form of a quadratic equation is y=ax^{2} +bx+c

The vertex form of a quadratic equation is y=a(x-h)^{2} +k

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

h=\frac{-b}{2a}

In this case, our quadratic equation is y=x^{2} -6x-16. Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

h=\frac{-b}{2a} ⇒ h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is y=x^{2} -6x-16

y=x^{2} -6x-16 ⇒ y=(3)^{2} -6(3)-16 ⇒ y=9-18-16 ⇒ y=-25

This y-value that we just found is our k-value.

Next, we are going to set up our equation in vertex form. As a reminder, vertex form is: y=a(x-h)^{2} +k

a: 1

h: 3

k: -25

y=(x-3)^{2} -25

Hope this helps!

3 0
3 years ago
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