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Tamiku [17]
3 years ago
11

Find the lowest value of the set of data this box-and-whisker plot represents.

Mathematics
2 answers:
wel3 years ago
5 0

Answer:

12

Step-by-step explanation:

its the lowest #

Delvig [45]3 years ago
4 0
The lowest set of data is 12
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A ladder leaning against a wall makes a 60° angle with the ground. The base of the ladder is 3 m from the building. How high abo
Marysya12 [62]

Answer:

The distance is 5.20m

Step-by-step explanation:

Here, we want to get the height of the ladder

To get this, we need to understand that we have a right triangle, with the base of the triangle as 3 m, the angle at the downward part is 60, and we want to get the height of the triangle

The angle here faces the height we want to calculate

This height is known as the opposite

What we have is the adjacent

Now, the trigonometric identity that relates the opposite and the adjacent is the tan

The tangent of an angle is the ratio of the opposite to the adjacent

Mathematically;

tan 60 = h/3

h = 3 tan 60

h = 5.20 m

The ladder is at a height of 5.20 m above the ground

7 0
3 years ago
Can someone please help me?
melamori03 [73]

Answer:

Answer is B

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Find the length of QP given Q is the midpoint of XF, PQ =2X+1, XF=7X-4, PF=X
nadezda [96]

Answer:

Therefore the length of QP = 3.4 units

Step-by-step explanation:

Given:

PQ = 2x + 1

XF = 7x - 4

PF = x

Q is the mid poimt of XF

∴ XQ = QF

QF = PQ - PF  ..........( Q - F - P )

     = 2x + 1 - x

∴ QF      = x + 1

∴ XQ = QF = x + 1

TO Find:

QP = ?

Solution:

By Addition Property we have

XP = XQ + QF+PF ..........(X-Q-F-P)\\\\

XF + PF =XQ + QF+PF ..........(X-Q-F-P)\\

Substituting the given values in above equation we get

(7x - 4) + x = (x +1) + (x +1) + x

8x -4 = 3x +2

8x - 3x + 4 + 2

5x = 6

∴ x = \frac{6}{5}

Now we require

QP = (2x + 1)

∴ QP = 2\times \frac{6}{5} +1\\\\QP = \frac{12+5}{5} \\\\QP =\frac{17}{5} \\\\\therefore QP = 3.4\ unit

Therefore the length of QP = 3.4 units

3 0
3 years ago
The outside temperature can be estimated based on how fast crickets chirp. At 104 chirps per minute, the temperature is 63 degre
Rasek [7]

Answer:

For 124 chirps per minute the temperature is 68 ºF.

For 68 chirps per minute the temperature is 54 ºF.

Step-by-step explanation:

Linear functions are those whose graph is a straight line. A linear function has the following form

f(x)=b+mx

b is the constant term or the y intercept. It is the value of the dependent variable when x = 0.

m is the coefficient of the independent variable. It is also known as the slope and gives the rate of change of the dependent variable.

We know that

  • At 104 chirps per minute, the temperature is 63 ºF.
  • At 176 chirps per minute, the temperature is 81 ºF.

This information can be converted to Cartesian coordinates (x, y). Where x = the number of chirps per minute and  y = the temperature in ºF.

To find a linear function that let us find the outside temperature from how fast crickets chirp we must:

  • Find the slope:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{81-63}{176-104}=\frac{1}{4}

  • Find the equation:

81=\frac{1}{4}\cdot 104+b

Solving for b

b=81-\frac{1}{4} (176)=37

Therefore, the linear function is

y=\frac{1}{4} \cdot x+37

Now, using this linear function we can know the temperature when we know the chirps per minute:

For 124 chirps per minute the temperature is:

y=\frac{1}{4} \cdot (124)+37=68

For 68 chirps per minute the temperature is:

y=\frac{1}{4} \cdot (68)+37=54

6 0
3 years ago
Put the following equation of a line into slope intercept form simplifying all fractions 10x-2y=6
Anarel [89]

Answer:

Slope-Intercept form:   y = m x + b

y = value of y corresponding to value of x

2 y = 10 x - 6

y = 5 x - 3         equation of line where m is the slope and -3 value of y when x                      

                         equals  zero

3 0
2 years ago
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