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julia-pushkina [17]
3 years ago
15

Evaluate h(8q2 - 2g) for h(x) = 7x+ 4q

Mathematics
1 answer:
Verdich [7]3 years ago
3 0

Answer:

56q2 - 10q

Step-by-step explanation:

1. the function is given h(x) = 7x + 4q

2. we should put (8q2 - 2q) instead of x

3. we should write when x = 8q2 - 2q

then it will be h(8q2 - 2q)= 7(8q2 - 2q) + 4q

4. then we should multiply the elements in the bracket with 7 then it will be 56q2 - 14q + 4q

5. then we should substract -14q + 4q then it will be -10

6. and answer comes 56q2 - 10q

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Answer:

In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus  three over root seven

Step-by-step explanation:

Given that sin ∅ =3/4 It means the ratio of the opposite side to the hypotenuse side is 3:4.

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