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AysviL [449]
3 years ago
9

Select True or False for each statement.

Mathematics
2 answers:
mote1985 [20]3 years ago
7 0
<h2>Answer:</h2>

For a real number a, a + 0 = a.  TRUE

For a real number a, a + (-a) = 1.  FALSE

For a real numbers a and b, | a - b | = | b - a |.  TRUE

For real numbers a, b, and c, a + (b ∙ c) = (a + b)(a + c).  FALSE

For rational numbers a and b when b ≠ 0, is always a rational number. TRUE

<h2>Explanation:</h2>

  • <u>For a real number a, a + 0 = a.  </u><u>TRUE</u>

This comes from the identity property for addition that tells us that<em> zero added to any number is the number itself. </em>So the number in this case is a, so it is true that:

a+0=a

  • For a real number a, a + (-a) = 1.  FALSE

This is false, because:

a+(-a)=a-a=0

For any number a there exists a number -a such that a+(-a)=0

  • For a real numbers a and b, | a - b | = | b - a |.  TRUE

This is a property of absolute value. The absolute value means remove the negative for the number, so it is true that:

\mid a-b \mid= \mid b-a \mid

  • For real numbers a, b, and c, a + (b ∙ c) = (a + b)(a + c).  FALSE

This is false. By using distributive property we get that:

(a + b)(a + c)=a^2+ac+ab+bc \\ \\ a^2+ab+ac+bc \neq a+(b.c)

  • For rational numbers a and b when b ≠ 0, is always a rational number. TRUE

A rational number is a number made by two integers and written in the form:

\frac{u}{v} \\ \\ v \neq 0

Given that a \ and \ b are rational, then the result of dividing them is also a rational number.

prohojiy [21]3 years ago
3 0

Answer:

A) True

B) False

C) True

D) False

E) True

Step-by-step explanation:

We are given the following statements in the question:

A) True

For  every real number, a, a + 0 = a. 0 is known as the additive identity.

B) False

For a real number a, a + (-a) = 0.

C) True

For a real numbers a and b, |a-b| = |b-a|

D) False

For real numbers a, b, and c, a + (b ∙ c) = (a + b)(a + c).

Counter example: For a = 2, b =  1, c = 3

a + (b.c) = (a + b)(a + c)\\2 + (1.3) \neq (2+1)(2+3)\\5\neq 15

E) True

For rational numbers a and b, b is not equal to zero, \frac{a}{b} is always a rational number.

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PLZ HELP!!! QUESTION IS BELOW! EXPLAIN YOUR ANSWER :D
hjlf

Answer:

  • 172.12 in²

Step-by-step explanation:

Consider the figure as 3 parts: semicircle with radius of 4 in, rectangle with 7x9 in and rectangle 6x14 in.

<u>Area of semicircle:</u>

  • A = 1/2*πr² = 1/2*3..14*4² = 25.12 in²

<u>Area of rectangles:</u>

  • 7*9 = 63 in²
  • 6*14 = 84 in²

<u>Total area:</u>

  • 25.12 + 63 + 84 = 172.12 in²
6 0
2 years ago
What is the expand form for 0.632
pav-90 [236]
0.600 is ur answer Hopes this helps u.
5 0
3 years ago
What are three consecutive integers whose product is 480 more than their sum?
Natali [406]

Answer:

The three numbers are 7 8 and 9

Step-by-step explanation:

Givens

  • Let the first number be n - 1
  • Let the second number be n
  • Let the third number = n + 1

Equation

(n - 1)(n)(n + 1) - (n-1 + n + n+1) = 480

Solution

Multiply (n - 1) and (n + 1) = (n - 1)*(n + 1) = n^2 - 1

Multiply the second integer by the result of the first and third: n (n^2 - 1)

Add the three integers together: (x - 1) + (n - 1) + n = 3n  Combine these 2 steps

n(n^2 - 1) - 3n = 480 Remove the brackets

n^3 - n - 3n = 480

n^3 - 4n = 480

n^3 - 4n - 480 = 0

Graph

The graph shows that the intercept point is n =8. This is the only way I can see to solve this cubic. There are no other real roots.

Answer

n - 1 = 7

n = 8

n + 1 = 9

Check

Product 7*8*9 = 504

Sum = 7 + 8 + 9 = 24

504 - 24 = 480 Which checks.

4 0
3 years ago
I have problems to found my answer, somebody can help me?
Thepotemich [5.8K]
So final step to do is you square root the x^2 and square root the 4000 which will get you answer of x = 63.2455532034 which can be 63.2. Hope this help!!
8 0
3 years ago
If cos A = 3 over 11, then which of the following is correct?
ziro4ka [17]

Answer:  The answer is (a) sec A = 11 over 3.



Step-by-step explanation: Given that Cosine of an angle 'A' is 3 over 11,

i.e.,

\cos A=\dfrac{3}{11}.

And we need to find which one of the given four options is correct.

We have the following relations between cosine, secant and cosecant of an angle from trigonometry.

\sec A=\dfrac{1}{\cos A}~~\textup{and}~~\csc A=\dfrac{1}{\sqrt{1-\cos^2 A}}.

Therefore,

\sec A=\dfrac{11}{3}

and

\csc A=\dfrac{1}{\sqrt{1-\frac{9}{121}}}=\dfrac{1}{\sqrt{\frac{112}{121}}}=\dfrac{11}{4\sqrt 7}.

Thus, the correct option is (a)  sec A = 11 over 3.

3 0
3 years ago
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