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lukranit [14]
3 years ago
7

How would you compare two ratios given in words?

Mathematics
1 answer:
zysi [14]3 years ago
7 0
Compared? By finding the LCM of the consequents of both the ratios, divide the LCM with the consequents, and finally, multiply both the numerator and the denominator of both the ratios with the answer to find out the compared ratio
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Please help and explain ( Brainliest for answer!)
Novosadov [1.4K]

Answer:

AD = 3

Step-by-step explanation:

Pythagoras theorem formula: a² + b² = c² (c being the hypotenuse, the longest side of the triangle).

Using this formula, you can easily say that c²-b²=a². c=5, b=4, making the equation 5² - 4² = a ².

Expanding the formula, you'll get 25 - 16 = a².

25 - 16 = 9.

This means that 9 = a².

To find a, you need to root 9. Using a calculator, you'll know that this number is 3, meaning that AD = 3.

7 0
3 years ago
EXPERT HELP I'LL GIVE BRAINLIEST:
grin007 [14]

Answer:

answer is 75 square feet

Step-by-step explanation:

area is length time width

8×6=48

to find area of triangle is length time witdht/height divided by 2

6×4=24/2=12

5×6=30/2=15

15+12+48=75

5 0
3 years ago
Read 2 more answers
Pless help I want to hang my self
Strike441 [17]
The answer is 27, but I might be wrong
8 0
3 years ago
If m(-12) =0 is the result of M(x) using the reminder theorem then what do -12 and 0 represent?
lions [1.4K]

Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that

Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as

Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.

Now consider two polynomials of degree 2. In this case we seek a single value of x such that

Hope this helped, Hope I did not make it to complated

Please give me Brainliest

3 0
3 years ago
Someone please help me!
Vlad1618 [11]

Answer:

A. x \leq -16  

B. b > 11

C. c \leq -13

D. x \geq -9

Step-by-step explanation:

<u>Given the following algebraic expression;</u>

A. \frac {3x}{4} \leq 12

We would simplify the equation by multiplying all through by 4;

4 * \frac {-3x}{4} \leq 12 * 4

-3x \leq 48

Divide both sides by -3;

x \leq -16

B. 5b - 28 > 27

Rearranging the equation, we have;

5b > 27 + 28

5b > 55

Divide both sides by 5

b > 11

C. 13c \leq -169

Divide both sides by 13

c \leq -13

D. 3x - 7 \geq 4x + 2

Collecting like terms, we have;

3x - 4x \geq 2 + 7

-x \geq 9

Divide both sides by -1

x \geq -9

8 0
3 years ago
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