Each person would receive 1 and an half cookies.
in other words 1 1/2
Answer:
he bought 1 pound
Step-by-step explanation:
1/8 + 7/8 = 7+1=8, same denominator so it stays, =8/8=1
Answer:
4 cookies
Step-by-step explanation:
Let the number of cookies he sold be c and that of brownies be b.
Assuming that brownies and cookies are the only type of baked goods sold,
b +c= 10 -----(1)
Amount of money received= $20
b(cost of brownie) +c(cost of cookie)= $20
2.50b +1.25c= 20 -----(2)
From (1): b= 10 -c -----(3)
Substitute (3) into (2):
2.50(10 -c) +1.25c= 20
Expand:
2.50(10) +2.50(-c) +1.25c= 20
25 -2.50c +1.25c= 20
-1.25c +25= 20
Being constants to 1 side:
-1.25c= 20 -25
-1.25c= -5
c= -5 ÷(-1.25)
c= 4
Thus, Joe sold 4 cookies.
Answer:
The correct answer is b) 1100 adults and 1400 students.
Step-by-step explanation:
To find this, set up a system of equations in which x is the number of students who attend and y is the number of adults who attend.
First start by creating an equation for money made.
5x + 10y = 18,000
Now write an equation for the amount that attend.
x + y = 2,500
Now multiply the bottom equation by -5 and add the equations together.
-5x - 5y = -12,500
5x + 10y = 18,000
5y = 5,500
y = 1,100
Since this is the number of adults, we can plug into an original equation to find the number of students.
x + y = 2,500
x + 1,100 = 2,500
x = 1,400
