F(x) = (x+3)(x-2) → f(x) = x² + x - 6
1st : The coefficient a > 0, the parabola opens upward,
2nd: The x-= intercepts are x = - 3 & x= +2 ( the values that render f(x) = 0
3rd: For x = 0, y = - 6 (this is y intercept)
The only figure that corresponds to those specifications is the 1st graph
Answer:
![y=\frac{5}{4}x+7](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B5%7D%7B4%7Dx%2B7)
Step-by-step explanation:
We can start by setting up what we know of the slope-intercept equation, which is the slope.
![y=\frac{5}{4}x+b](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B5%7D%7B4%7Dx%2Bb)
Now, we can use the given point to find the y-intercept.
![2=\frac{5}{4}(-4)+b\\ 2=-5+b\\b=7](https://tex.z-dn.net/?f=2%3D%5Cfrac%7B5%7D%7B4%7D%28-4%29%2Bb%5C%5C%202%3D-5%2Bb%5C%5Cb%3D7)
And now we are able to write the slope-intercept equation.
![y=\frac{5}{4}x+7](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B5%7D%7B4%7Dx%2B7)
I hope this helps!
Answer:
depending of the activity, learning subject, the hour or the class
Step-by-step explanation:
I am bore it seems that you are and thanks for the points :D
Answer:
read this
Step-by-step explanation:
In mathematics, the domain of definition (or simply the domain) of a function is the set of "input" or argument values for which the function is defined. That is, the function provides an "output" or value for each member of the domain. Conversely, the set of values the function takes on as output is termed the image of the function, which is sometimes also referred to as the range of the function.
Answer:
Step-by-step explanation: It would be 7/20