Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Here, Sin Ф = P / H
Sin 31 = x / 430
0.515 = x /430
x = 430 * 0.515
x = 221.45
In short, Your Answer would be 221.45
Hope this helps!
<span>4(9n-9)
= 4*9n -4*9 (distributive property)
= 36n -36
The correct answer is c. </span>36n -36~
Do Pythagorean theorem. If you don't know what that is...
Do A squared plus B squared Equals C squared and you will get your answer for the shape. Then calculate the area
