Answer:
- the value of the function changes sign in the interval
- the function is monotonic in the interval
Step-by-step explanation:
All polynomial functions are continuous, so we know from the intermediate value theorem that if the expression on the left changes sign in the interval [-2, 1] then there will be a zero in that interval. If the function is monotonic in the interval, there can only be one zero.
a) For f(x) = x^3 +x +3 = (x^2 +1)x +3, the values at the ends of the interval are ...
f(-2) = (4+1)(-2) +3 = -7
f(-1) = (1 +1)(-1) +3 = 1
The function value goes from -7 to +1 in the interval, so there exists at least one root in that interval.
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b) The derivative of the function is ...
f'(x) = 3x^2 +1
This is positive for any x, so is positive in the interval [-2, -1]. That is, the function is continuously increasing in that interval, so cannot have more than one crossing of the x-axis. There is exactly one root in the interval [-2, -1].
It would be -50 because the rule is subtract by 2 then 4 then 6 then 8 and etc.
WARNING THIS IS THE WRONG ANSWER in case any of you look at this
Answer:
x=3
Step-by-step explanation:
Let's solve your equation step-by-step.
2(10−13x)+9x=−34x+71
Step 1: Simplify both sides of the equation.
2(10−13x)+9x=−34x+71
Simplify:
−17x+20=−34x+71
Step 2: Add 34x to both sides.
−17x+20+34x=−34x+71+34x
17x+20=71
Step 3: Subtract 20 from both sides.
17x+20−20=71−20
17x=51
Step 4: Divide both sides by 17.
17/17x=51/17
x=3
Hope this help!!!
It's 1000
Sort of a trick question I guess.
Answer:
<em>(n - 5)(n + 5) </em>
Step-by-step explanation:
a² - b² = (a - b)(a + b)
n² - 25 = n² - 5² = <em>(n - 5)(n + 5)</em>