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maw [93]
2 years ago
14

By which reason can it be proven that triangles DAB and DAC are congruent?

Mathematics
2 answers:
Mashutka [201]2 years ago
5 0

Answer:

AAS

Step-by-step explanation:

Vinil7 [7]2 years ago
4 0

Answer:

AAS

Step-by-step explanation:

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charity is four times as old as her daughter. she is also six years younger than her husband. The sum of their ages ten years to
Pachacha [2.7K]

Answer:

36years

Step-by-step explanation:

Let charity present age be x

Charity daughter present age be y

Charity husband present age be z

If the sum of their ages ten years to come is 117, then;

10+x+10+y+10+z = 117

30+x+y+z = 117

x+y+z = 87 ... 1

If charity is four times as old as her daughter, then;

x = 4y

y = x/4 ... 2

If she is also six years younger than her husband, then;

x = z- 6

z = x+6 .. 3

Substitute 2 and 3 into 1;

x + x/4 + (x+6) = 87

Multiply through by 4

4x + x + 4(x+6) = 4(87)

5x+4x+24 = 348

9x = 348 - 24

9x = 324

x = 324/9

x = 36

hence Charity is 36years old today

5 0
3 years ago
The vocbulary of adding and subtracting radicals
motikmotik
Adding and subtracting radical expressions.
7 0
3 years ago
What’s 3 times 6 over 7 **MULTIPLY
Amanda [17]

Would it be 2.5??? I think it would but not completely sure

7 0
3 years ago
Read 2 more answers
HELPP!!what is the answer to this picture above^
nasty-shy [4]

Answer:

\fbox{ \fbox { \sf{Distance  =  \sf{15 \: units}}}}

{ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}

Step-by-step explanation:

\star{ \:  \sf { \: Let \: the \: points \: be \: A \: and \: B}}

\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}

\underline{ \underline{ \tt{Finding \: the \: distance}}}

\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(18 - 6)}^{2}  +  {(15 - 6)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(12)}^{2}  +  {(9)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{144 + 81}}}

\mapsto{ \sf{Distance =  \sqrt{225} }}

\mapsto{ \sf{Distance =  \sqrt{ {15}^{2} } }}

\mapsto{  \boxed{\sf{Distance = 15 \: units}}}

\underline{ \underline {\tt{Finding \: the \: Midpoint}}}

\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2}  \: , \:  \frac{y1 + y2}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2}  \: , \:  \frac{6 + 15}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{24}{2}  \: , \:  \frac{21}{2} )}}

\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

3 0
3 years ago
_+6 +2 = 6 + 10<br><br> Find the missing number
Sauron [17]
574=30303 equals that
4 0
3 years ago
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