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Leokris [45]
2 years ago
14

Write an equation parallel to x - 2y = 4 that passes through the point (-8, 2).

Mathematics
1 answer:
castortr0y [4]2 years ago
7 0

Answer:

y=1/2x+6

Step-by-step explanation:

Change to slope intercept form: y=1/2x-2

Take out the b term

Plug in point (-8, 2)

Get b as 6

Plug in b

Get y=1/2x+6

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За – 6а + 2 = 8а + 20 – 5а
Luda [366]

Answer:

a = -3

Step-by-step explanation:

3a - 6a + 2 = 8a + 20 - 5a

Combine Like Terms

-3a + 2 = 3a + 20

       -2            -2

-------------------------------------

-3a = 3a + 18

-3a  -3a

-------------------------------------

-6a = 18

----   ----

-6     -6

a  =  -3

4 0
2 years ago
A store that sells skis buys them from a manufacturer at a wholesale price of $60. The store's markup rate is 50%. What price do
horsena [70]

Answer:

$90

Step-by-step explanation:

To solve this problem, you simply multiply $60 by 50%. Remember to change 50% into its decimal form (50% -> 0.5).

60 x 0.5 = 30

Now we add 30 to the original price of $60 to get our final answer.

$60 + 30 = $90

3 0
2 years ago
Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, -1).
ira [324]
Line:
3x+y=7
y=-3x+7

Slope of Perpendicular Line: 1/3x

For the perpendicular line to contain point (6,-1) the y-intercept would be (0,1), thus the equation of the line would be y=1/3x+1

y=1/3x+1

5 0
2 years ago
-4(5+n) = -12 need help​
user100 [1]

First, simplify out the brackets:

-20 - 4n = -12

Then, combine like terms by moving the -20 to the other side

-4n = -12 + 20

-4n = 8

Divide by -4 on both sides to isolate the n

n = 8/-4

n = -2

7 0
3 years ago
Read 2 more answers
Find the area of the trapezoid.<br> Answer options: 8sqrt2, 4sqrt3, 12.0, 16sqrt2
Elis [28]

Answer:

=  8sqrt2

Step-by-step explanation:

Area of a trapezium is given by the formula;

1/2(a+b)h ;

Where a and b are the parallel sides and h is the perpendicular height.

a = 3 cm, b= 5 cm

To get; h, we use the Pythagoras theorem;

h² = 3² - 1²

   h² = 8

h = √8

  = √4√2

 = 2√2

Thus;

Area = 1/2(3 +5) 2√2

         = 1/2 ×8 × 2√2

       <u>  = 8√2 cm² or  8sqrt2 cm²</u>

8 0
3 years ago
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