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NemiM [27]
3 years ago
5

Which of the following are solutions to the equation below?

Mathematics
1 answer:
lana66690 [7]3 years ago
8 0

Answer:

F. - 4

Hope it help

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At noodle & company restaurant, the probability that a customer will order a nonalcoholic beverage is .46. Find the probabil
skelet666 [1.2K]

Answer:

0.0021

Step-by-step explanation:

Given:

Probability of ordering a nonalcoholic beverage is, P(N)=0.46

Number of samples are n=10

Now, the complement of event 'N' is not ordering a nonalcoholic beverage.

Therefore, P(\overline N)=1-P(N)=1-0.46=0.54

Now, for a sample of '10' customers, the probability of not ordering a non alcoholic beverage is product of their individual probabilities as all these events are independent events.

Therefore, probability that none of the 10 will order a nonalcoholic beverage is given as:

=[P(\overline N)]^{10}\\\\=(0.54)^{10}\\\\=0.0021

5 0
3 years ago
See attached photo. Please Help ASAP and Explain
nignag [31]
(sinx)^2 = 1 when cosx is 0 at pi/2 and 3pi/2
cosx = 1 when sinx is 0 at 0

therefore, A
3 0
3 years ago
Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 33% of all homeowners are ins
Lina20 [59]

Answer:

(a) The probability mass function of <em>X</em> is:

P(X=x)={4\choose x}\ (0.33)^{x}\ (1-0.33)^{4-x};\ x=0,1,2,3...

(b) The most likely value for <em>X</em> is 1.32.

(c) The probability that at least two of the four selected have earthquake insurance is 0.4015.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number among the four homeowners  who have earthquake insurance.

The probability that a homeowner has earthquake insurance is, <em>p</em> = 0.33.

The random sample of homeowners selected is, <em>n</em> = 4.

The event of a homeowner having an earthquake insurance is independent of the other three homeowners.

(a)

All the statements above clearly indicate that the random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 4 and <em>p</em> = 0.33.

The probability mass function of <em>X</em> is:

P(X=x)={4\choose x}\ (0.33)^{x}\ (1-0.33)^{4-x};\ x=0,1,2,3...

(b)

The most likely value of a random variable is the expected value.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected value of <em>X</em> as follows:

E(X)=np

         =4\times 0.33\\=1.32

Thus, the most likely value for <em>X</em> is 1.32.

(c)

Compute the probability that at least two of the four selected have earthquake insurance as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{4\choose 0}\ (0.33)^{0}\ (1-0.33)^{4-0}-{4\choose 1}\ (0.33)^{1}\ (1-0.33)^{4-1}\\\\=1-0.20151121-0.39700716\\\\=0.40148163\\\\\approx 0.4015

Thus, the probability that at least two of the four selected have earthquake insurance is 0.4015.

3 0
3 years ago
What is the value of Y
Allisa [31]

Answer:

The value of y is one

Step-by-step explanation:

Hope it helps

8 0
2 years ago
Read 2 more answers
X^2 + 8 = 3<br>please help! show steps.​
Alborosie

x² + 8 = 3

x² = 3 - 8

x² = -5

x = √-5 or undefined

6 0
3 years ago
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