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Makovka662 [10]
3 years ago
12

PLS HELP PLS

Mathematics
1 answer:
77julia77 [94]3 years ago
4 0

Red Perimeter= 4u X π= 4uπ

Blue Perimeter= u X π= uπ

Red Area= 2u X 2u X π= 4u2π

Blue Area= u X u X π= u2π

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three friends go to a book fair . alvin speends 2.60 . prabhjot spends 4 times as much as alvin . stephanie spends 3.45 less the
blsea [12.9K]

Answer:

6.95

Step-by-step explanation:

to find how much stephanie spends for first we will find how much probhjot spends and then subtract 3.45 dollars from that value alvin spends 2.60 dollars

prohbjot spends 4 times as much as alvin or

4× 2.60=10.4

so prohbjot spends 10.4 dollars

stephanie spends3.45 dollars less than prohbjot or

10.4 -3.45 =6.95

so stephanie spends <u>6.95 </u>dollars

7 0
3 years ago
Which expression represents the employees take home pay after deductions
Juliette [100K]

The expression 0.15(x-350) would be the proper equation.

7 0
3 years ago
Hey plsss help meeeeee
nalin [4]

Answer:

The first, third, and fourth answer choices represent a function.

Step-by-step explanation:

A relation is a relationship between sets of values. The two quantities that are being related to each other are the input (x-variable) and the output (y-variable). But relations in general aren't always a good way to relate between x and y.

Say that I have situation where I want to give <em>x </em>dollars to the cashier so he can change them to <em>y</em> quarters. Here is a "example" of the relation:

Dollars (x) | Quarters (y)            

----------------------------------              

       0       |          0                      

        1       |          4                      

       2       |          8

       2       |          12

Do you see something wrong here? Yes! We all know that you can't exchange 2 dollars for 12 quarters. You can only exchange 2 dollars for 8 quarters and only 8 quarters. This is a general reason why we don't rely on general relations for real-life situations. One x-variable does not exactly map to one and only one y-variable.

However, a relation that can map one x-variable to one and only one y-variable is known as a function. Let's make the above example an actual function to prove a point:

Dollars (x) | Quarters (y)            

----------------------------------              

       0       |          0                      

        1       |          4                      

       2       |          8

       3       |          12

Now, the 3 dollars make 12 quarters as it should. This is how a function should look like.

There are two ways to check if a relation is a function. On a relation, table, or a set of ordered pairs, you have to make sure there is no "x-variable" that repeats. All x-values of a relation have to be unique in order to be a function. On a graph, you can also perform the Vertical Line Test. If you draw vertical lines over a relation and if the lines cross only once, then it is a function. If not, it fails the Vertical Line Test.

So to answer you're question, the first, third, and fourth choices are functions because they all have unique x-variables. The second choice is not a function because it fails the Vertical Line Test.

7 0
2 years ago
the length and width of a rectangular patio are (x+8) feet and (x+6) feet, respectively. If the area of the patio is 160 square
lorasvet [3.4K]
<span>(x + 8)  (x + 6) = 160
x² +6x +8x +48 = 160
</span>x² +6x +8x +48 - 160 =0
<span>x² +14x -112=0

You have to calculate the discriminant.

(Please mark be brainliest)

</span>
6 0
3 years ago
PLEASE ANSWER QUICKLY AS POSSIBLE WILL GIVE BRAINLYEST TO FIRST CORRECT
Tems11 [23]

Answer:

Soln:

Step-by-step explanation:

Here,

Base(b) =9

Opposite/Perpendicular (p)= x

Hypotenus (h) = 24

We know,

(p)^2 = (h)^2 - (b)^2

(x)^2 = (24)^2 - (9)^2

x^2 = 576 - 81

x^2 = 495

x = root under 495

6 0
1 year ago
Read 2 more answers
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