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earnstyle [38]
3 years ago
8

What would be A' after I dilation using a scale factor of 1/2

Mathematics
1 answer:
noname [10]3 years ago
8 0

Answer:

A) (-5,0)  

Step-by-step explanation:

B)  (-2, 4)

C)  (-2, -3)

Hope this helped!

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c will be the answer g g g t g

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Find the midpoint of the line segment whose endpoints are (-2, 5) and (6, -9).
Katen [24]
We know that when A=(x_A,y_A) and B=(x_B,y_B) the midpoint of the line segment AB is given by:

M=\left(\dfrac{x_A+x_B}{2},\dfrac{y_A+y_B}{2}\right)

Here A=(-2,5) and B=(6,-9) so:

M=\left(\dfrac{x_A+x_B}{2},\dfrac{y_A+y_B}{2}\right)=\left(\dfrac{-2+6}{2},\dfrac{5+(-9)}{2}\right)=\\\\\\=\left(\dfrac{4}{2},\dfrac{5-9}{2}\right)=\left(2,\dfrac{-4}{2}\right)=\boxed{\left(2,-2\right)}

8 0
3 years ago
What is the length of segment A.B.
madreJ [45]

Answer:

The distance between A and B is <em>l(AB) = </em>13 units

Step-by-step explanation:

Given:

let,

A ≡ ( x1, y1 ) ≡ ( 0, 12 )

B ≡ ( x2, y2 ) ≡ ( 5, 0 )

To Find:

Length AB = ?

Solution:

Distance Formula for the distance between the two points ( x1, y1 ) and ( x2, y2 ) we have,

l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}

On substituting the above values we will get,

l(AB) = \sqrt{((5-0)^{2}+(0-12)^{2} )}\\l(AB)=\sqrt{(5^{2} +(-12)^{2} } \\l(AB)=\sqrt{(25+144)}\\ l(AB)=\sqrt{169} \\l(AB)=13\ unit

Therefore the distance between A and B is <em>l(AB) = </em>13 units

5 0
4 years ago
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