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To construct a line perpendicular to line AB and passing through an external point M.
Step 1:- Keep point A as center and draw a circle using compass opened with a width equal to radius AM.
Step 2:- Similarly, Keep point B as center and draw another circle using compass opened with a width equal to radius BM.
Step 3:- The two circles drawn so far would cut at two points, first point is M and second point is N.
Step 4:- Join the two points M and N using straightedge.
Step 5:- Therefore, we have a line MN that is perpendicular to line AB.
5(-11)+6y=-37
-55+6y=-37
6y=18
y=3
Answer:
h is directly proportional to B and inversely proportional to A
Step-by-step explanation:
Answer:
(r^2 - r - 1)(r^2 + r - 1).
Step-by-step explanation:
r^4 - 3r^2 + 1
We need to make this into a perfect square so the r^4 and the 1 fit the bill but not the -3r^2 so we have to correct for that.
A perfect square would be:
r^4 - 2r^2 + 1 ( = (r^2 - 1)^2 )
But we need -3r^2 so we add - r^2 at the end:
= (r^4 - 2r^2 + 1) - r^2 So now we have the difference of 2 squares and we write:
(r^2 - 1)^2 - r^2
= (r^2 - 1 - r)(r^2 - 1 + r)
= (r^2 - r - 1)(r^2 + r - 1)
