Answer:
(x+5)²(x²+5)
Step-by-step explanation:
Given two functions x²+5 and x²+10x+25, to get their Lowest common factor, we need to to first factorize x²+10x+25
On factorising we have:
x²+5x+5x+25
= x(x+5) +5(x+5
= (x+5)(x+5)
= (x+5)²
The LCM can be calculated as thus
| x²+5, (x+5)²
x+5| x²+5, (x+5)
x+5| x²+5, 1
x²+5| 1, 1
The factors of both equation are x+5 × x+5 × x²+5
The LCM will be the product of the three functions i.e
(x+5)²(x²+5)
This hives the required expression.
Answer:
Coordinates:
(-1, -2), (-1, -4), (-3, -2), (-3, -4)
Answer:
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
Zeroe of the function is such velue of x at which f(x)=0.
1. Consider the function 
Zeros are:
Zero 
has multiplicity of 1, zero 
has multiplicity of 2, zero 
has multiplicity of 5.
At or the graph of the function crosses the x-axis, at the graph of the function touches the x-axis.
2. Consider the function 
Zeros are:
Zero has multiplicity of 1, zero 
has multiplicity of 2.
At the graph of the function crosses the x-axis, at the graph of the function touches the x-axis.
Answer:
x = 198
Step-by-step explanation:
1/2x + 101 = 200.
Subtract 101 from both sides.
1/2x = 99
You want x by itself, therefore you have to get rid of 1/2. The opposite of diving by two, is multiplying by two.. therefore, you must multiply both sides by two.
x=99*2
x=198
