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Sever21 [200]
3 years ago
9

HELP ITS DUE TODAY!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
RoseWind [281]3 years ago
4 0

Answer/Step-by-step explanation:

x + 74° + 20° = 180° (sum of interior angles of a triangle)

x + 94° = 180°

x = 180° - 94° (subtraction property of equality)

x = 86°

y = 74° + 20° (exterior angle theorem of a triangle)

y = 94°

y + z + 32° = 180° (sum of interior angles of a ∆)

Plug in the value of y

94 + z + 32 = 180

z + 126 = 180

z = 180 - 126

z = 54°

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Find the value of a if given points are collinear (5,1) (3,2) and (1,a)​
Ksenya-84 [330]

9514 1404 393

Answer:

  a = 3

Step-by-step explanation:

The x-values 5, 3, 1 form an arithmetic sequence. The y-values will do the same: 1, 2, a = 1, 2, 3 -- a common difference of +1.

  a = 3

8 0
3 years ago
Simplify: (8^2)^3<br> please help:)
alexira [117]

Answer:

262144

Step-by-step explanation:

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6 0
3 years ago
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Check whether the relation R on the set S = {1, 2, 3} is an equivalent
kozerog [31]

Answer:

R isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.

Step-by-step explanation:

Let S denote a set of elements. S \times S would denote the set of all ordered pairs of elements of S\!.

For example, with S = \lbrace 1,\, 2,\, 3 \rbrace, (3,\, 2) and (2,\, 3) are both members of S \times S. However, (3,\, 2) \ne (2,\, 3) because the pairs are ordered.

A relation R on S\! is a subset of S \times S. For any two elementsa,\, b \in S, a \sim b if and only if the ordered pair (a,\, b) is in R\!.

 

A relation R on set S is an equivalence relation if it satisfies the following:

  • Reflexivity: for any a \in S, the relation R needs to ensure that a \sim a (that is: (a,\, a) \in R.)
  • Symmetry: for any a,\, b \in S, a \sim b if and only if b \sim a. In other words, either both (a,\, b) and (b,\, a) are in R, or neither is in R\!.
  • Transitivity: for any a,\, b,\, c \in S, if a \sim b and b \sim c, then a \sim c. In other words, if (a,\, b) and (b,\, c) are both in R, then (a,\, c) also needs to be in R\!.

The relation R (on S = \lbrace 1,\, 2,\, 3 \rbrace) in this question is indeed reflexive. (1,\, 1), (2,\, 2), and (3,\, 3) (one pair for each element of S) are all elements of R\!.

R isn't symmetric. (2,\, 3) \in R but (3,\, 2) \not \in R (the pairs in \! R are all ordered.) In other words, 3 isn't equivalent to 2 under R\! even though 2 \sim 3.

Neither is R transitive. (3,\, 1) \in R and (1,\, 2) \in R. However, (3,\, 2) \not \in R. In other words, under relation R\!, 3 \sim 1 and 1 \sim 2 does not imply 3 \sim 2.

3 0
3 years ago
1.Write 6,730,000 in scientific notation.
miskamm [114]

Answer:

6.73 X 10 to the sixth power.

1.33 X 10 to the fifth power.

9.77 X 10 to the twenty-second power.

Step-by-step explanation:

7 0
3 years ago
Maria and Josie went to the movies and spent $3.75 altogether on snacks. Let t = the price of a movie ticket. Write an expressio
nydimaria [60]
From the question we know that Maria and Josie went to the movies and spent a total amount of money, which should be the price of the tickets added to the price of the snacks.

Knowing that the price of the snacks is $3.75 and the price of the tickets is t, it looks like all that is left is to assign a variable to the total amount of maney they spent at the movies and write out the equation.

If we let the total amount of money they spent be x, then x= t+3.75, whcih should be your answer!
6 0
3 years ago
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