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If we are drawing altitude from R the PQ will be base of this triangle. So we can say Median from R will cut on Midpoint of PQ. So firstly we will find mid point of PQ Which is S given as below:
P(4,-1) , Q (-2,7)
Let Co-ordinate of S is (x,y)
So
So midpoint of PQ is S(1,3).
Now we can find equation of RS
Co-ordinate of R is (9,9) and and S is (1,3).
In general equation of line from two point
and 
is
So equation of RS is
So the equation of median is 6x - 8y = -66
P(4,-1) , Q (-2,7)
Let Co-ordinate of S is (x,y)
So
So midpoint of PQ is S(1,3).
Now we can find equation of RS
Co-ordinate of R is (9,9) and and S is (1,3).
In general equation of line from two point
So equation of RS is
So the equation of median is 6x - 8y = -66
According to Vieta's formula, if 
are solutions of quadratic equation 
, then:
In our case:
In our case: