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DIA [1.3K]
3 years ago
6

Question 17 Multiple Choice Worth 1 points) (06.02 LC) Which of these is the algebraic expression for "5 times the sum of 2 and

y?"
A. 5 • 2 + y
B. 2 + 5 • y
C. 2(5 + y)
D. 5(2 + y)​
Mathematics
1 answer:
Setler [38]3 years ago
3 0

Answer:

D 5(2 + y)​

Step-by-step explanation:

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Answer:

a. 60

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Step-by-step explanation:

all you have to do is plug in the numbers that are given to you for the missing variables and then solve it regularly.

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Write expression as a sine or cosine of an angle.<br>cos 94° cos 18° + sin 94° sin 18° ​
MArishka [77]
<h3>Answer:  cos(76)</h3>

=========================================================

Explanation:

The original expression is of the pattern cos cos + sin sin. This pattern matches the second identity in the hint. Specifically, we'll say the following:

cos(A - B) = cos(A)cos(B) + sin(A)sin(B)

cos(A)cos(B) + sin(A)sin(B) = cos(A - B)

cos(94)cos(18) + sin(94)sin(18) = cos(94 - 18)

cos(94)cos(18) + sin(94)sin(18) = cos(76)

----------

We can verify this by use of a calculator. Make sure your calculator is in degree mode.

  • cos(94)cos(18) + sin(94)sin(18) = 0.24192
  • cos(76) = 0.24192

Both expressions give the same decimal approximation, so this helps confirm the two expressions are equal. You could also use the idea that if x = y, then x-y = 0. Through this method, you'll subtract the left and right hand sides and you should get (very close to) zero.

6 0
3 years ago
(8Q) Tell whether the function exhibits damped oscillation. If it does, identify the damping factor and tell whether the damping
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Answer:

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Step-by-step explanation:

We can easily solve this question by using a graphing calculator or any plotting tool.

The function is

f(x) = (√11)*cos(3.7x)

Which can be seen in the picture below

We can notice that f(x) is a cosine with maximum amplitude of  (√11). Neither this factor nor the multiplication of x by 3.7 serve as a damping factor since they are constants.

f(x) does not present any dampening

5 0
3 years ago
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Please please please help!!!
dalvyx [7]

9514 1404 393

Answer:

  2

Step-by-step explanation:

Fill in the argument value and look up the function value on the graph.

  (f\circ f)(-2) = f(f(-2)) = f(2) = \boxed{2}

7 0
2 years ago
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