Thanks for all the help how can i repay?

I need a little help! Can someone check my work? It's a written response with linear systems.

andreyandreev [35.5K]

Answer:

I'd say you need to be more specific.

Step-by-step explanation:

"Different" doesn't tell you much.

Consider the equations ...

y = 2x + 1
4x - 2y = -2

These equations are "different", but they are dependent.

_____

I'd mentally (or actually) put the equations in the same form and compare the coefficients of x and y. If they have different ratios, the system is independent and consistent.

If they have the same ratio, the system will not have a single solution. Whether there is no solution or an infinite number of solutions depends on the constant, which I would examine next.

The system above can be put in the form

2x -y = -1
4x -2y = -2

In both cases, the ratio of the x coefficient to the y coefficient is 2/-1 = 4/-2 = -2. This means the lines are at least parallel, if not identical. The numbers in the second equation are all 2 times the numbers in the first equation, so the equations are dependent, and there are an infinite number of solutions. (Both describe the same line.)

If the second equation were 4x -2y = 1, then the two equations would be describing parallel lines, so they would be called inconsistent.

5 0

3 years ago

-2/3 divided by (-15)

Travka [436]

2 over 45 just so that you know

6 0

2 years ago

Find the squares of (y+3)

emmasim [6.3K]

Answer:

Since we know that

(a+b)

2

=a

2

+2ab+b

2

(a−b)

2

=a

2

−2ab+b

2

Now,

(i)

(x+3y)

2

=x

2

+2×x×3y+(3y)

2

=x

2

+6xy+9y

2

(ii)

(2x−5y)

2

=(2x)

2

−2×2x×5y+(5y)

2

=4x

2

−20xy+25y

2

(iii)

(a+

5a

1

)

2

=a

2

+2×a×

2a

1

+(

2a

1

)

2

=a

2

+1+

4a

2

1

(iv)

(2a−1a)=(1a)

2

(1a)

2

=1a

2

Answer

8 0

2 years ago

Solve in attachment....

olga2289 [7]

Answer:

A)2

Step-by-step explanation:

we would like to integrate the following definite Integral:

$\displaystyle \int_{0} ^{1} 5x \sqrt{x} dx$

use constant integration rule which yields:

$\displaystyle 5\int_{0} ^{1} x \sqrt{x} dx$

notice that we can rewrite √x using Law of exponent therefore we obtain:

$\displaystyle 5\int_{0} ^{1} x \cdot {x}^{1/2} dx$

once again use law of exponent which yields:

$\displaystyle 5\int_{0} ^{1} {x}^{ \frac{3}{2} } dx$

use exponent integration rule which yields;

$\displaystyle 5 \left( \frac{{x}^{ \frac{3}{2} + 1 } }{ \frac{3}{2} + 1} \right) \bigg| _{0} ^{1}$

simplify which yields:

$\displaystyle 2 {x}^{2} \sqrt{x} \bigg| _{0} ^{1}$

recall fundamental theorem:

$\displaystyle 2 ( {1}^{2}) (\sqrt{1} ) - 2( {0}^{2} )( \sqrt{0)}$

simplify:

$\displaystyle 2$

hence

our answer is A

8 0

2 years ago

Read 2 more answers

The table shows the heights and the lengths of several rectangles.

Harman [31]

Answer:

Weak Positive Correlation

Step-by-step explanation: I think that’s correct not 100 percent sure

8 0

2 years ago