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3 years ago

Thanks for all the help how can i repay?

Mathematics

1 answer:

scoundrel [369]3 years ago

7 0

Answer:

All work and answers are in the picture

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In circle E shown below, the measure of ∠AED is 98°:

dangina [55]

It's 225 hope this helps put brainliest answer need to get to the next rank

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3 years ago

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Pyramid A is a square pyramid with a base side length of 9 inches and a height of 4 inches. Pyramid B has a volume of 8,100 in.

JulijaS [17]

Answer:

Option d. 75 times.

Step-by-step explanation:

Side length of a square pyramid of Pyramid A = 9 inches

height of pyramid A = 4 inches

$\text{Volume of the squared pyramid}=a^2(\frac{1}{3})h$

where,

a = sides, h = height

$=9^2(\frac{1}{3})\times 4$

$=81(\frac{1}{3})\times 4$

= 27 × 4

= 108 inches³

and the volume of pyramid B = 8100

Now we will divide volume of pyramid B by the volume of pyramid A

$=\frac{8100}{108}$

= 75

Therefore, the volume of pyramid B is 75 times bigger than pyramid A.

Option d is the answer.

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2 years ago

What is the image of (4, -1) after a reflection over the line y = x?

Mrrafil [7]

Answer:

the correct answer is -4, -1

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11 months ago

How many centimeters are in<br> 9 inches? 1 in. = 2.54 cm

kirill [66]

Answer:

22.86 centimeters, or roughly 23

Step-by-step explanation:

2.54*9=22.86

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3 years ago

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Consider F and C below. F(x, y) = x4y5i + x5y4j, C: r(t) = t3 − 2t, t3 + 2t , 0 ≤ t ≤ 1 (a) Find a function f such that F = ∇f.

vovikov84 [41]

$\mathbf f(x,y)=x^4y^5\,\mathbf i+x^5y^4\,\mathbf j$

We want a scalar function $f(x,y)$ whose gradient is equivalent to the vector field. That means

$\dfrac{\partial f}{\partial x}=x^4y^5\implies f(x,y)=\dfrac{x^5y^5}5+g(y)$
$\dfrac{\partial f}{\partial y}=x^5y^4\implies x^5y^4=x^5y^4+\dfrac{\mathrm dg}{\mathrm dy}$
$\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C$

So (a)

$f(x,y)=\dfrac{x^5y^5}5+C$

which means (b)

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(\mathbf r(1))-f(\mathbf r(0))=f(-1,3)-f(0,0)=-\dfrac{243}5-0=-\dfrac{243}5$

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2 years ago