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tigry1 [53]
3 years ago
9

Somebody can help me please

Mathematics
1 answer:
sergey [27]3 years ago
7 0

Answer:

sorry but i don't know how...just doing my job

to get 400 points. sorry ;{

Step-by-step explanation:

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Evaluate the expression without using the calculator 8^1/3
allsm [11]

Answer:

= 2.67

Step-by-step explanation:

Given: 8^1/3

We have to find the value of the given fraction which can be done by dividing the denominator value with the numerator value

                                  \frac{8^1}{3} \\

 The power of 8 is '1', so, the value of numerator is 8.

                                    \frac{8}{3}

The value of the fraction is calculated by dividing 3 by 8.

                         = 2.67

8 0
3 years ago
Tiffany is packing her bags for her vacation. She has 8 8 unique toy animals, but only 4 4 fit in her bag. How many different gr
mote1985 [20]

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https://www.evensi.us/arizona-cardinals-green-bay-packers-tv-12218/280846604

5 0
3 years ago
En el estante de un negocio hay 2 tipos de tarros de la misma mermelada y marca. El tarro más alto tiene el doble de altura que
Ipatiy [6.2K]

Answer:

tarro corto

Step-by-step explanation:

Aquí tenemos que comprar el frasco que tiene el menor costo por volumen.

h_1 = Altura del frasco corto

h_2 = La altura del frasco alto es el doble que el del frasco corto. = 2h_1

d_1 = Diámetro del frasco corto

d_2 = El diámetro del frasco alto es la mitad del frasco corto = \dfrac{1}{2}d_1

El volumen de un cilindro es \pi \dfrac{d^2}{4}h

La razón de los volúmenes de los frascos es

\dfrac{V_1}{V_2}=\dfrac{\pi\dfrac{d_1^2}{4}h_1}{\pi\dfrac{d_2^2}{4}h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{d_2^2h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{(\dfrac{1}{2}d_1)^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{\dfrac{1}{4}d_1^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{1}{\dfrac{1}{2}}\\\Rightarrow \dfrac{V_1}{V_2}=2\\\Rightarrow V_1=2V_2

El costo del frasco corto por unidad de volumen es

\dfrac{8000}{V_1}=\dfrac{8000}{2V_2}=\dfrac{4000}{V_2}

El costo del frasco alto por unidad de volumen es

\dfrac{4500}{V_2}=\dfrac{4500}{V_2}

\dfrac{4000}{V_2}

Entonces, el costo del frasco corto por unidad de volumen es menor que el costo por unidad de volumen del frasco alto.

Por lo tanto, deberíamos tomar el frasco corto.

5 0
3 years ago
Combine the following sets of terms.
DanielleElmas [232]

Let's simplify step-by-step To understand :)

3x2−7x−(x2+3x−9)

Distribute the Negative Sign:

=3x2−7x+−1(x2+3x−9)

=3x2+−7x+−1x2+−1(3x)+(−1)(−9)

=3x2+−7x+−x2+−3x+9

Combine Like Terms:)

=3x2+−7x+−x2+−3x+9

=(3x2+−x2)+(−7x+−3x)+(9)

=2x2+−10x+9

Answer :)

=2x2−10x+9


HOPE THIS HELPS

3 0
3 years ago
This is question is Estimate. 3245 dived 8 Choose 1 answer: A 4 b 40 c 400 d 4000
trapecia [35]

Answer:

<h3>The answer is option C.</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
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