Tan x /(1 +sec x) + (1+sec x) /tan x
Tan x=sin x / cos x
1+ sec x=1 +1/cos x=(cos x+1)/cos x
Therefore:
tan x /(1 +sec x) =(sin x/cos x)/(cos x+1)/cos x=
=(sin x * cos x) / [cos x* (cos x+1)]=sin x /(Cos x+1)
(1+sec x) /tan x=[(cos x+1)/cos x] / (sin x/cos x)=
=[cos x(cos x+1)]/(sin x *cos x)=(cos x+1)/sin x
tan x /(1 +sec x) + (1+sec x) /tan x=
=sin x /(Cos x+1) + (cos x+1)/sin x=
=(sin²x+cos²x+2 cos x+1) / [sin x(cos x+1)]=
Remember: sin²x+cos²x=1⇒ sin²x=1-cos²x
=(1-cos²x+cos²x+2 cos x+1) / [sin x(cos x+1)]=
=2 cos x+2 / [sin x(cos x+1)]=
=2(cos x+1) / [sin x(cos x+1)]=
=2 /sin x
Answer : tan x /(1 +sec x) + (1+sec x) /tan x= 2/sin x
Answer:
x>11 is the solution to both equations.
Step-by-step explanation:
I apologize for late response I've been busy lately. Anyways here ya go! :
From what I understand it wants us to solve "9x-4>95" so that's what I'll do.
add 4 to each side
9x>99
divide each side by 9
x>11 is the solution to 9x-4>95
For 4x+10>54
subtract 10 from each side
4x>44
divide each side by 4
x>11 is the solution to 4x+10>54
Answer:
AAS
Step-by-step explanation:
Answer:
5/7
Step-by-step explanation:
Simplify by finding common factors and dividing both the numerator and denominator by it.
40/ 56 = 20/28(divided by 2) = 10 / 14 (divided by 2) = 5/7 ( divided by 2)
Hope this helps.
Please mark brainiest
