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soldi70 [24.7K]
3 years ago
13

A negative correlation means ________. Group of answer choices there is a relationship between two variables, but it is not stat

istically significant two variables increase together, but they are associated with an undesirable outcome one variable decreases as the other increases a third variable eliminates a correlational relationship
Mathematics
1 answer:
lisov135 [29]3 years ago
5 0

Answer: one variable decreases as the other increases

Step-by-step explanation:

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Can you help me with this one
exis [7]
5 is b and 1 is a
1 is A because just change the x value with the number in the table for x and see if y matches like
Y=-2x+6
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4 =-2*1+6

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Day is x, y is depending on x and your going to add .4 to everything. But it’s growing .2 every day so it’s
Y=0.2x+0.4

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7 0
3 years ago
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Pls pls help i realy need help
lisov135 [29]

Answer:

a <= 3

Step-by-step explanation:

4 0
3 years ago
How many lines of symmetry are in the regular pentagon <br><br>O A. 3<br>O B. 5<br>O C. 7<br>O D. 9​
stiks02 [169]

Answer:

5

Step-by-step explanation:

There is one line of symmetry for each side of the pentagon.

7 0
3 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)
vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

x^{\frac{2}{3}}+y^{\frac{2}{3}}=4

We have to find the equation of tangent line to the given curve at point (-3\sqrt3,1)

By using implicit differentiation, differentiate w.r.t x

\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0

Using formula :\frac{dx^n}{dx}=nx^{n-1}

\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}

\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}

\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}

Substitute the value x=-3\sqrt3,y=1

Then, we get

\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}

\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}

Slope of tangent=m=\frac{1}{\sqrt3}

Equation of tangent line with slope m and passing through the point (x_1,y_1) is given by

y-y_1=m(x-x_1)

Substitute the values then we get

The equation of tangent line is given by

y-1=\frac{1}{\sqrt3}(x+3\sqrt3)

y-1=\frac{x}{\sqrt3}+3

y=\frac{x}{\sqrt3}+3+1

y=\frac{x}{\sqrt3}+4

This is required equation of tangent line to the given curve at given point.

8 0
3 years ago
18 % of 90 is what number
Lyrx [107]
18 percent of 90 is 16.2
6 0
3 years ago
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