Solve the compound inequality below:
1 answer:
3 - 8r <= 3 + 4r
3 - 3 <= 4r + 8r
0 <= 12r
0 <= r
-6+ 4r < 2+ 4r
4r - 4r < 2 + 6
0 < 8
all real numbers
The "or" statement means combining the sets of solutions.
combined sets = all real numbers
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