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sweet [91]
3 years ago
14

Helpppppppppp plzzzzz

Mathematics
2 answers:
seropon [69]3 years ago
7 0
4(y-3) = 4*y -4*3
= 4y - 12
Artemon [7]3 years ago
6 0

Answer:

4y - 12

Step-by-step explanation:

Given

4(y - 3) ← multiply each of the terms inside the parenthesis by 4

= 4y - 12

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Find the GCF.<br> 6m3n and 8mn2
Liono4ka [1.6K]

Answer:

2mn

Step-by-step explanation:

6m^3n,\:8mn^2

Find the GCD of 6,\:8:

6

=2\cdot \:3

8

=2\cdot \:4

=2\cdot \:2\cdot \:2

So the prime factor common to 6, 8 is:

2

So the factor common to 6m^3n,\:8mn^2:

=2mn

6 0
3 years ago
Bill spent 50% of his savings on school supplies, then he spent 50% of what was left on lunch. If he had $6 left after lunch, ho
Lera25 [3.4K]

If he spent half his savings on supplies and the other half on lunch he shouldn't have money left over. It's a trick question.

6 0
3 years ago
Read 2 more answers
Linda can complete 4.5 long divisions in 1 hour. how many can she finish in 6.5 hours?
coldgirl [10]
Is there an A.B.C. or D to choose from?
8 0
3 years ago
Identify the percent of change as an increase or decrease. Then find the percent of change. Round to the nearest tenth of a perc
bazaltina [42]

I'll do the first two problems to get you started. All problems shown will use the same formula.

===========================================

Problem 4

The formula to use is

C = 100*(B-A)/A

where

A = old value

B = new value

C = percent change

In this case, A = 12 and B = 36, so

C = 100*(B-A)/A

C = 100*(36-12)/12

C = 100*(24/12)

C = 100*2

C = 200%

We have a 200% increase. It is an increase because the value of C is positive.

===========================================

Problem 5

Use the same formula as in the previous problem. This time,

A = 75 is the old value

B = 25 is the new value

C = 100*(B-A)/A

C = 100*(25-75)/75

C = 100*(-50/75)

C = 100*(-2/3)

C = -66.6667%

C = -66.7%

The value of C is negative, so we have a percent decrease of roughly 66.7%

8 0
3 years ago
Simplify -3x³y²(-4x²y•y•y•y•y)²
AnnZ [28]

-3x^3y^2(-4x^2 \underbrace{y\cdot y\cdot y\cdot y}_{y^4})^2\\\\=(-3)(-4)(x^3x^2)(y^2y^4)\\\\=12x^{3+2}y^{2+4}\\\\=\boxed{12x^5y^6}\\\\Used:\\\\a^n\cdot a^m=a^{n+m}

3 0
3 years ago
Read 2 more answers
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