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Mama L [17]
3 years ago
7

Help plz I need this grade

Mathematics
1 answer:
Sindrei [870]3 years ago
7 0

Answer: (1,3)

Step-by-step explanation:

5y=10+5x

y=2+x

      plug in (2+x) for y

21x+7(2+x)=42

21x+7x+14=42

           -14  -14

28x=28

x=1

       plug in 1 for x

y=2+1

y=3

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Plz, help me answer this.
Finger [1]

Answer:

B. 5

Step-by-step explanation:

-15 / -3

Both are negative so they cancel each other out.

15 / 3 equals 5

7 0
3 years ago
Read 2 more answers
Given the function g(x) = 7x - 14 find its inverse function.
Dafna11 [192]

Answer:

The inverse is 1/7x +2

Step-by-step explanation:

y = 7x - 14

Exchange x and y

x = 7y-14

Solve for y

Add 14 to each side

x+14 = 7y-14+14

x+14 = 7y

Divide each side by 7

(x+14)/7 = 7y/7

1/7x +2 = y

The inverse is 1/7x +2

6 0
3 years ago
Read 2 more answers
The first number of three consecutive even integers equals the sum of the second and third. Find the three numbers.
stiv31 [10]

Answer:

x=2x+6 is the equation that to solve for the smallest.

The three numbers are -6, -4 , and -2.

Step-by-step explanation:

Let x be the smallest of three consecutive even integers.

The next even integer would then have to be x+2 (because x+1 is odd if x is even).

The third one in this sequence would have to be x+4 (because x+3 is odd if x is even).

We are given the first of these numbers equals the sum of the second and third.

So we have x=(x+2)+(x+4).

Combine like terms on right hand side:

x=x+x+2+4

Simplify the combining:

x=2x+6

Subtract 2x on both sides:

x-2x=6

Simplify left hand side:

-x=6

Multiply both sides by -1:

x=-6

If x=-6,  then the three mentioned numbers are:

x=-6

x+2=-6+2=-4

x+4=-6+4=-2

The three numbers are -6, -4 , and -2.

6 0
3 years ago
A) Show that the equation 20-x^3-7x^2=0 can be rearranged to give x=20/x^2 - 7
AVprozaik [17]

Answer:

Step-by-step explanation:

      20-x^3-7x^2=0

a)

  • Add x^3 to both sides of the equation:     20-7x^2=x^3
  • Divide both sides by x^2:    \frac{20}{x^2} -\frac{7x^2}{x^2} =\frac{x^3}{x^2}  ⇒  \frac{20}{x^2} -7 =x

b)

    x_1=\frac{20}{(x_0)^2} -7

⇒ x_1=\frac{20}{(-9)^2} -7

⇒ x_1=-\frac{547}{81}

    x_2=\frac{20}{(x_1)^2} -7

⇒ x_2=\frac{20}{(-\frac{547}{81})^2} -7

⇒ x_2=-6.561443673...

   x_3=\frac{20}{(x_2)^2} -7

⇒ x_3=\frac{20}{(-6.561443673...)^2} -7

⇒ x_3=-6.535451368...

c) approximation to the location of one of the roots of the equation.  Each iteration gives a slightly more accurate value of a root x.

4 0
3 years ago
Find the slope between two points : ( - 5,5 ) and ( 3, - 5 )
vampirchik [111]
(-5,5)(3,-5)
slope = (y2 - y1) / (x2 - x1)
slope = (-5-5) / (3 - (-5)
slope = -10/(3 + 5)
slope = -10/8 = - 5/4 <== ur slope
8 0
4 years ago
Read 2 more answers
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