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lisabon 2012 [21]
4 years ago
6

Paula has sold 256 worth of items for the fundraiser. she has sold 32 more than Steve. how much has Steve sold​

Mathematics
1 answer:
Vinil7 [7]4 years ago
8 0

answer=288

you add 256 into 32 to get 288 so then you get 288

(I think)

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9. < Q ; < S and QR = SR . select the correct statement for the two triangles . What rule proves the congruence ? ( 1point
motikmotik
The theorem proving the triangles' congruence is Angle-side-angle (ASA) and the angle corresponding to Q is S; therefore, the answer is B.
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ololo11 [35]

Answer:

g(-4)=2.5

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Step-by-step explanation:

g signifies the line, ad the number in parenthesis is the x value. so for other problems like this, just find the y value of the graphed object at the x value listed. hope this helped :)

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3 years ago
Consider the function g(x) =-3(x-2) 2 + 3 what is the vertex
Margarita [4]

Answer:

The vertex is (2, 3)

Step-by-step explanation:

This is because the parent equation for problems like these is y=a(x-h)2 +k. The vertex is found through (h, k) and so with 2 as H and 3 as K, the vertex is (2,3).

4 0
3 years ago
Find derivative problem<br> Find B’(6)
dalvyx [7]

Answer:

B^\prime(6) \approx -28.17

Step-by-step explanation:

We have:

\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]

We can move the constant outside:

\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]

Now, we will utilize the product rule. The product rule is:

(uv)^\prime=u^\prime v+u v^\prime

We will let:

\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t

Then:

\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1

(The derivative of u was determined using the chain rule.)

Then it follows that:

\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}

Therefore:

\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]

By simplification:

\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0
3 years ago
What is the quotient 36 divided by 6
Dafna11 [192]

Answer:

6

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36/6

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1 2. 3. 4. 5. 6

3 0
3 years ago
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