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2 years ago

10

Andrew needs to call his 8 baseball teammates to make plans for a party at the end of the season if each call takes 5 minutes ho

w much time will he spend making the calls?
A. 1/3 hour
B.40/100 hour
C.2/3 hour
D.3/4 hour

1 answer:

Alex_Xolod [135]2 years ago

5 0

Answer:

C

Step-by-step explanation:

8*5=40 minutes

There is a total of 60 minutes.

So:

40/60 = 4/6 = 2/3

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2(m+1)

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2 years ago

Cheryl moves houses. Her old house is 3 kilometers from her new house. How many meters is it from the old house to the new house

d1i1m1o1n [39]

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3 years ago

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Harrizon [31]

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Step-by-step explanation:

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3 years ago

Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285

Mkey [24]

Answer:

$Highway = 155\ miles$

$City = 130\ miles$

Step-by-step explanation:

Given

$Highway = 31mi/gallon$

$City = 26mi/gallon$

$Total\ Miles = 285$

$Total\ Gallons = 10$

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

$c + h = 10$ ---- gallons used

and

$31h + 26c = 285$ --- distance travelled

In the first equation, make c the subject

$c = 10 - h$

Substitute 10 - h for c in the second equation

$31h + 26c = 285$

$31h + 26(10 - h) = 285$

Open bracket

$31h + 260 - 26h = 285$

Collect like terms

$31h - 26h = 285 - 260$

$5h = 25$

Make h the subject

$h = \frac{25}{5}$

$h = 5$

Substitute 5 for h in $c = 10 - h$

$c = 10 - 5$

$c = 5$

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

$Highway = 31 * 5$

$Highway = 155\ miles$

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

$City = 26 * 5$

$City = 130\ miles$

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%20%7B%2018%20%5E%20%7B%20n%20%2B%201%20%7D%20%5Ctimes%203%20%5E%20%7B%201%20-%20n%20%7

Rufina [12.5K]

Answer:

$4 \times {3}^{n + 3}$

Step-by-step explanation:

$\frac{ {18}^{n + 1} \times {3}^{1 - n}}{ {2}^{n - 1} }$

$\frac{ {3}^{2n + 2} \times {2}^{n + 1} \times {3}^{1 - n} }{ {2}^{n - 1} }$

${3}^{2n + 2} \times {2}^{2} \times {3}^{1 - n}$

${3}^{2n + 2} \times 4 \times {3}^{1 - n}$

$= 4 \times {3}^{n + 3}$

8 0

3 years ago

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