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3 years ago

Will give brainliest answer

Mathematics

1 answer:

nexus9112 [7]3 years ago

5 0

Answer:

Step-by-step explanation:

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side.

We see that: 4.1 + 1.3 < 8.4

=> Can't form a triangle from 4.1 cm, 8.1 cm and 1.3 cm

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Can someone answer this please

GarryVolchara [31]

32 players = 16 matches ( 32/2)

16 players = 8 matches ( 16/2)

8 players = 4 matches (8/2)

4 players = 2 matches ( 4/2)

2 players = 1 match

16 + 8 +4 +2 +1 = 31 matches

4 0

4 years ago

YALL PLEASE PLEASE DIS A TEST!!

ollegr [7]

The answer would be 7 becuase if rounded

3 0

3 years ago

Find the quadratic function that fits the following data. which one function fits.

Oksana_A [137]

Answer:

Step-by-step explanation:

The general rule for the quadratic function is

$y=ax^2+bx+c$

Use the data from the table:

$y(50)=130\Rightarrow 130=a\cdot 50^2+b\cdot 50+c\\ \\y(70)=130\Rightarrow 130=a\cdot 70^2+b\cdot 70+c\\ \\y(90)=200\Rightarrow 200=a\cdot 90^2+b\cdot 90+c$

We get the system of three equations:

$\left\{\begin{array}{l}2500a+50b+c=130\\ \\4900a+70b+c=130\\ \\8100a+90b+c=200\end{array}\right.$

Subtract these equations:

$\left\{\begin{array}{l}4900a+70b+c-2500a-50b-c=130-130\\ \\8100a+90b+c-2500a-50b-c=200-130\end{array}\right.\Rightarrow \left\{\begin{array}{l}2400a+20b=0\\ \\5600a+40b=70\end{array}\right.$

From the first equation

$b=-120a$

Substitute it into the second equation:

$5600a+40\cdot (-120a)=70\Rightarrow 800a=70,\\ \\ a=\dfrac{7}{80},\\ \\ b=-120\cdot \dfrac{7}{80}=-\dfrac{21}{2}=-10.5$

So,

$2500\cdot \dfrac{7}{80}+50\cdot (-10.5)+c=130\Rightarrow 218.75-525+c=130\\ \\c=130-218.75+525=436.25$

The quadratic function is

$y=\dfrac{7}{80}x^2-10.5x+436.25\\ \\y=0.0875x^2-10.5x+436.25$

4 0

3 years ago

There are 100 students at a college who have taken a course in calculus, 110 who have taken a course in discrete mathematics, an

vesna_86 [32]

Answer:

110 students

Step-by-step explanation:

The number of students who have only taken calculus is given by the number of students who have taken calculus minus the students who have taken both classes:

$C =100 -50\\C= 50\ students$

The number of students who have only taken discrete mathematics given by the number of students who have taken discrete mathematics minus the students who have taken both classes:

$D =110 -50\\C= 60\ students$