9514 1404 393
Answer:
300
Step-by-step explanation:
There are 25 ways to select the first student. After that student is removed from the selection pool for the second student, there are 24 ways to select the second student. This gives 25·24 = 600 ways to select 2 students <em>in a particular order</em>.
Since we don't care about the order, we can divide this number by the number of ways two students can be ordered: AB or BA, 2 ways.
600/2 = 300
There are 300 ways to pick a combination of two students from 25.
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<em>Additional comments</em>
This sort of selection (2 out of 25) has a formula for it, and an abbreviation for the formula.
"n choose k" can be written nCk or C(n, k)
The function is a ratio of factorials:
nCk = n!/(k!(n-k)!)
If you can typeset this, it is written ...
This is different from the formula for the number of <em>permutations</em> of n things taken k at a time. That would be written nPk or P(n, k) = n!/(n-k)!.
Complete Question
Stillwater Junior High divides students into teams taught by a group of teachers. The table shows the number of students in each team.
Team{Number of Students}
Acers{78}
Blazers{80}
Outbacks{83}
Quasars{77}
Voyagers{82}
<u>Total-400</u>
Answer:
(A)81/399
Step-by-step explanation:
The probability that the Principal selects a voyager on the first try is:
82/400
Since another student is to be selected, the <u>total population has reduced by 1 </u>and the <u>number of voyagers likewise has been reduced by 1.</u>
Therefore:
Probability that another voyager is selected on the second try =
81/399
<u>The correct option is A.</u>
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Answer:
He have 43 bills of 10 and 13 bills of 5
Step-by-step explanation:
5x + 10y = 495
x + y = 56
Isolate x:
x = 56 - y
Substitute in the first equation:
5(56 - y) +10y = 495
280 -5y +10 y = 495
5y = 495 -280
5y = 215
y = 215/5
y= 43
Now substitute the value of y to find x:
x = 56 - y
x = 56 - 43
x = 13
