Seventy-six and one tenth
A + 5 > -7....subtract 5 from both sides
a > -7 - 5
a > - 12
Answer:

Step-by-step explanation:

Hello :
<span>A(-2, -5), B(-3, 2), and C (1, -2)
calculate : AB² , AC² ,BC²
</span> AB² = ( -3 +2 )² + ( 2 +5 )² =50
AC² = ( 1 +2 )² + ( -2 +5 )² =18
BC² = ( 1 +3 )² + ( -2 - 2 )² = 32
by petagor rule : AB² = AC² + BC²....(<span>ABC is a </span>right triangle in : C )
So the easiest way to do this is to convert this standard form equation into slope-intercept form, which is y = mx+b (m = slope, b = y-intercept). The slope indicates whether the line is going upwards and downwards and at what rate, and the y-intercept is where the line crosses the y-axis.
Firstly, subtract both sides by 6x: 
Next, divide both sides by 8 and your slope-intercept form will be: 
So with this equation, since the slope is negative, the line is going downwards. You will graph this line so that when x increases by 3, y decreases by 2 and so that the line passes (0,-4). Here are some of the points on this line to help you:
(0,-4), (3, -6), (6,-8), etc.