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3 years ago

Which answer choice is equivalent to the expression below?

Mathematics

1 answer:

Bess [88]3 years ago

8 0

Answer:

the answer would be -13n-23

Step-by-step explanation:

first you want to distribute the brackets

-7(2+n) = -14-7n

+(-9-6n)

-9-6n

-14-7n-9-6n

combine the n value with an n value and an integer that doesn't have an n value

-7n-6n-14-9

= -13n-23

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Solve the system by using a matrix equation

Sergeu [11.5K]

Answer:

Option A is correct (17,11).

Step-by-step explanation:

6x - 9y = 3

3x - 4y =7

it can be represented in matrix form as $\left[\begin{array}{cc}6&-9\\3&4\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}3\\7\end{array}\right]$

A= $\left[\begin{array}{cc}6&-9\\3&4\end{array}\right]$

X= $\left[\begin{array}{c}x\\y\end{array}\right]$

B= $\left[\begin{array}{c}3\\7\end{array}\right]$

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (6*-4) - (-9*3)

= (-24)-(-27)

= (-24) + 27 = 3

so, |A| = 3

Adj A= $\left[\begin{array}{cc}-4&9\\-3&6\end{array}\right]$

A⁻¹ = $\left[\begin{array}{cc}-4&9\\-3&6\end{array}\right]$ /3

A⁻¹ = $\left[\begin{array}{cc}-4/3&3\\-1&2\end{array}\right]$

X= A⁻¹ B

X= $\left[\begin{array}{cc}-4/3&3\\-1&2\end{array}\right] *\left[\begin{array}{c}3\\7\end{array}\right]$

X= $\left[\begin{array}{c}(-4/3*3) + (3*7)\\(-1*3) + (2*7)\end{array}\right]$

X= $\left[\begin{array}{c}-4+21\\-3+14\end{array}\right]$

X= $\left[\begin{array}{c}17\\11\end{array}\right]$

x= 17, y= 11

solution set= (17,11).

6 0

3 years ago

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What is 5.082 * 45 decomposed

swat32

72.3 is the correct answer because it is correcto

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Free_Kalibri [48]

Answer:

Step-by-step explanation:

Use the formula: change of y over change of x.

When you do that, your systems should look like this:

x1 = 2

y1 = 4

x2 = 6

y2 = 12

After that you plug these number into the corresponding variable.

(12 - 4) / (6 - 2) = 8/4 which equals 2.

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80 $\geq$ p-20

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